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2 years ago

What is is a true statement?

Mathematics

2 answers:

Temka [501]2 years ago

8 0

Answer:

The Second option, all parallelagrams are quadralatterals.

Step-by-step explanation:

because it for 1, makes the most sense, 2 most look like rhombuses which is a tilted square.

inessss [21]2 years ago

3 0

The second one all parallelograms are quadrilaterals

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What is the equation to find a square in 6-8??

VikaD [51]

Answer: 2 Squared is the answer

Step-by-step explanation:

Squared with 8 and 6 imagine 6 parcel and 8 sides.

It minus's to equal the equation 2.

3 0

2 years ago

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

I will try to give as many details as possible.

First of all, I just would like to say:

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Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

2 years ago

Please show your work

Paladinen [302]

Answer:

see in the picture, the perimeter of this rectangle is

2( x + 3x) = 8x but the perimeter is 65.6

=> 8x = 65.6

<=> x = 65.6/8

=> x = 8.2

7 0

2 years ago

Simplify (3v5+8v3−10v2)−(−12v5+4v3+14v2) . Write answer in standard form.

Tatiana [17]

Answer:

15v^5+4v^3-24v^2

Step-by-step explanation:

Distribute the Negative Sign:

=3v5+8v3−10v2+−1(−12v5+4v3+14v2)

=3v5+8v3+−10v2+−1(−12v5)+−1(4v3)+−1(14v2)

=3v5+8v3+−10v2+12v5+−4v3+−14v2

Combine Like Terms:

=3v5+8v3+−10v2+12v5+−4v3+−14v2

=(3v5+12v5)+(8v3+−4v3)+(−10v2+−14v2)

=15v5+4v3+−24v2

Answer:

=15v5+4v3−24v2

Hope this helps! :)

5 0

2 years ago

In a building that is 854 ft tall, a serial killer at a height of 858.7 ft took a shot at unsuspecting victim who was located 10

UNO [17]

Answer:109.20

Step-by-step explanation:simple answer son

6 0

2 years ago