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dmitriy555 [2]
2 years ago
12

Triangle with side lengths 4 feet, 5 feet, and 8 feet

Mathematics
1 answer:
Masteriza [31]2 years ago
7 0

Answer:

<em><u>Yed</u></em><em><u>,</u></em><em><u> </u></em><em><u>it </u></em><em><u>is </u></em><em><u>possible</u></em><em><u> </u></em><em><u>as</u></em>

Step-by-step explanation:

4 + 5 = 9

So, sum of two sides of a triangle is always greater than the third side(largest one)

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jeka94
Factors of -8 that add up to 2: 4 & -2

(x + 4)(x - 2)

Set x to 0 for both and solve

x = -4

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Solve and check <br> 2/3y =6 <br> A.1/9 <br> B.1/4<br> C.9<br> D.4
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\frac{2}{3}y=6\ \ \ \ |divide\ both\ sides\ by\ \frac{2}{3}\ /multiply\ by\ \frac{3}{2}/\\\\y=6\cdot\frac{3}{2}\\\\y=\frac{6}{1}\cdot\frac{3}{2}\\\\y=\frac{\not6^3\cdot3}{1\cdot\not2_1}\\\\y=\frac{3\cdot3}{1\cdot1}\\\\y=\frac{9}{1}\\\\\boxed{y=9}\leftarrow answer\ \boxed{C}

check:\\\\/put\ the\ value\ of\ y=9\ to\ the\ equation\ \frac{2}{3}y=6/\\\\\frac{2}{3}\cdot9=6\\\\\frac{2}{3}\cdot\frac{9}{1}=6\\\\\frac{2}{\not3_1}\cdot\frac{\not9^3}{1}=6\\\\\frac{2}{1}\cdot\frac{3}{1}=6\\\\2\cdot3=6\\\\\boxed{6=6}\leftarrow TRUE


8 0
4 years ago
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You be the teacher. a student graphs the equation y = 4 is the student correct explain your reason​
Kisachek [45]

Answer:

Step-by-step explanation:

8 0
3 years ago
How many real solutions does the equation 8x^2 − 10x + 15 = 0 have?
Nimfa-mama [501]

Answer:

The correct option is (A) No real solution.

Step-by-step explanation:

The expression provided is a quadratic equation.

8x^{2}-10x+15=0

The roots of a quadratic equation are:

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Here,

a = 8

b = -10

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The conditions to determine real and complex roots are:

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Compute the value of b^{2}-4ac as follows:

b^{2}-4ac=(-10)^{2}-(4\times 8\times15)\\\\

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The equation has two complex roots.

Thus, the correct option is (A).

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3 years ago
Question 3
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Answer:

14.50 * 1.32 = $19.14

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