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2 years ago

What volume in liters of carbon dioxide will be produced by the reaction of 18.5 liters of oxygen gas at STP?

Chemistry

1 answer:

agasfer [191]2 years ago

8 0

Answer:

0.16 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 0.012 moles of O₂

The molar ratio of O₂ to CO₂ is 5:3. The moles of CO₂ produced are 3/5 × 0.012 mol = 0.0072 mol.

Step 3: Calculate the volume occupied by 0.0072 moles of CO₂ at standard temperature and pressure

At STP, 1 mole of CO₂ occupies 22.4 L.

0.0072 mol × 22.4 L/1 mol = 0.16 L

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Answer:

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3 years ago

Robert has 4 grams of a substance and Jill has 10 grams of the same substance. Which of the following statements is true?

ELEN [110]

If Robert has 4 grams of a substance and Jill has 10 grams of the same substance Jill's sample will weigh more than Robert's sample.

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2 years ago

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GrogVix [38]

Answer:

i think A

Explanation:

6 0

3 years ago

The density of benzene is 0.879g/mL. The volume (with 1 decimal) of 131.9g sample of benzene is how many mL?

timurjin [86]

Answer:

150.1 mL

Explanation:

Step 1: Given data

Density of benzene (ρ): 0.879 g/mL

Mass of the sample of benzene (m): 131.9 g

Volume of the sample of benzene (V): ?

Step 2: Calculate the volume of the sample of benzene

Density is an intrinsic property. It is equal to the quotient between the mass and the volume of the sample of benzene.

ρ = m/V

V = m/ρ

V = 131.9 g/(0.879 g/mL)

V = 150.1 mL

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3 years ago

What is the molarity of a solution composed of 5.85 g of potassium iodide, KI, dissolved

Troyanec [42]

Answer:

0.282 M

General Formulas and Concepts:

Chemistry - Solutions

Reading a Periodic Table
Using Dimensional Analysis
Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define

5.85 g KI

0.125 L

Step 2: Identify Conversions

Molar Mass of K - 39.10 g/mol

Molar Mass of I - 126.90 g/mol

Molar Mass of KI - 39.10 + 126.90 = 166 g/mol

Step 3: Convert

$5.85 \ g \ KI(\frac{1 \ mol \ KI}{166 \ g \ KI} )$ = 0.035241 mol KI

Step 4: Find Molarity

M = 0.035241 mol KI / 0.125 L

M = 0.281928

Step 5: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.281928 M ≈ 0.282 M

7 0

3 years ago