Answer:
removing the methanol as it is formed
Explanation:
One of the ways to drive the equilibrium position towards the right is to remove one of the products formed.
According to Me Chatelier's principle, the imposition of a constraint on a system in a equilibrium causes the equilibrium position to shift towards a new position that annuls the constraint. Hence, removing the methanol causes the equilibrium position to shift to the far right in order to reestablish equilibrium according to Le Chatelier's principle.
<span>Take the inversion of density: 1mL/13.6 g and multiply it by the conversion factor 453.6 g/ 1 lb and the given 5.00 lb. Units for mass (grams) and units for weight (lbs) cancel leaving only units of volume. I believe it should be 167 mL or 0.167 L</span>
Answer:
Explanation:
HA(aq)+H2O(l)⟺H3O+(aq)+A−(aq)(1)
you need to solve for the Ka value. To do that you use
Ka=[H3O+][A−][HA](2)
Another necessary value is the pKa value, and that is obtained through pKa=−logKa
The procedure is very similar for weak bases. The general equation of a weak base is
BOH⟺B++OH−(3)
Solving for the Kbvalue is the same as the Ka value. You use the formula
Kb=[B+][OH−][BOH](4)
The pKb value is found through pKb=−logKb
The Kw value is found withKw=[H3O+][OH−].
Kw=1.0×10−14(5)
Cross-linked polymers are strong and heat - resistant hence they can be used for this purpose.
A polymer is obtained by the combination of small molecules called monomers. A polymer consists of a regular repeating unit of small molecules called monomers.
A cross-linked polymer is a polymer in which covalent bonds are used to join polymer chains together. Cross-linked polymers are strong and heat - resistant hence they can be used for this purpose.
Learn more: brainly.com/question/17638582
Answer:
–2.23 L
Explanation:
We'll begin by calculating the final volume. This can be obtained as follow:
Initial pressure (P₁) = 1.03 atm
Initial volume (V₁) = 3.62 L
Final pressure (P₂) = 2.68 atm
Final volume (V₂) =?
P₁V₁ = P₂V₂
1.03 × 3.62 = 2.68 × V₂
3.7286 = 2.68 × V₂
Divide both side by 2.68
V₂ = 3.7286 / 2.68
V₂ = 1.39 L
Finally, we shall determine the change in volume. This can be obtained as follow:
Initial volume (V₁) = 3.62 L
Final volume (V₂) = 1.39 L
Change in volume (ΔV) =?
ΔV = V₂ – V₁
ΔV = 1.39 – 3.62
ΔV = –2.23 L
Thus, the change in the volume of her lung is –2.23 L.
NOTE: The negative sign indicate that the volume of her lung reduced as she goes below the surface!
