We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
Answer:
f(x) = 3x⁴ - 
- 17x + 
Step-by-step explanation:
To find f'(x), we will follow the steps below:
We will start by integrating both-side of the equation
∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx
f(x) = 3x⁴ - - 17x + C
Then we go ahead and find C
f(1) = 8
so we will replace x by 1 in the above equation and solve for c
f(1) = 3(1)⁴ - 
- 17(1) + C
8 = 3 - 
- 17 + C
C =8 - 3 + 17 +
C = 22 +
C =
C =
f(x) = 3x⁴ - - 17x +
Answer:
-2/7
Step-by-step explanation:
Going from (7,-1) to ( 21,-5) we see x (the 'run') increasing by 14 and y (the 'rise') decreasing by 4. Thus, the slope of the line connecting these two points is m = rise/run = -4/14, or -2/7.
Easy bruh
Answer:
6w^3
Step-by-step explanation:
It can't be any answer with cubed in it because that would be volume. So, A and C magically vanish. If we know that the length of a cube is w that means that all sides are w. There are six faces on a cube. If we want to find surface area we will have to add up the area of all faces. the area of one face will be w^2. We multiply that number by six and we get 6w^3.
