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olganol [36]
2 years ago
10

Bradley owns 2 surfboards and 4 wet suits. If he takes one surfboard and one wet suit to the beach, how many different combinati

ons can he choose?​
Mathematics
1 answer:
photoshop1234 [79]2 years ago
7 0

Answer:

The answer is eight

Step-by-step explanation:

4*2=8

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Please helpppppppppppppp
Helen [10]

Answer:

90/23

Step-by-step explanation:

First, you want to start in the parentheses. 5-6=-1, then multiply it by -2. Since a negative multiplied by a negative is a positive, -2*-1=2. -3^2=-9. 2+8=10. Then -9 times 10= -90. Then, we move on to the bottom. 5--2=7. 4^2=16, and -2(2)=-4. So -5(7) + 16-4=-23. Now, the equation should look like this, -90/-23. Put the negatives together and you get 90/23.

6 0
3 years ago
What are the solutions of the equation 6x2 +5x+1 = 0 ?
STatiana [176]

Answer:

Step-by-step explanation:

6x^2+5x+1=0

Descr= b^2-4ac

Descr= 25-24=1

X1= (-b+√descr)/2a = (-5+1)/12= -1/3

X2= (-b-√descr)/2a = (-5-1)/12= -1/2

6 0
3 years ago
Read 2 more answers
Which graph represents the linar function y=1/3x-4?
spin [16.1K]

Answer:

(0,-4)

Step-by-step explanation:

4 0
3 years ago
Two number cubes are tossed. Find P(1, then 2 or 3).
Andreyy89

Answer:

1/2

Step-by-step explanation:

6 0
3 years ago
Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
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