Answer:
Option "A" is the correct answer to the following statement.
Explanation:
Cross-sectional observational estimates are based on findings with Various data that exist in various groups in the same period. This indicates that there was no other procedure wad made, so no factors are influenced by the analyst.
In this situation, there were various age groups involved in the Experiment at the same time.
Answer:
Check the answers below
Explanation:
- The per instrument cost of the bank is $0.25. Assuming uniform cheque value, the 24 million remittances across 10000 cheque will mean per cheque value of 2400. If this amount can be invested at 8% p.a., then daily investment income will be approx = 2400 * 8% /365 = $ 0.526
- Now for the company to jus about cover the cost of the cheque processing, the time should reduce by (assuming fractional time in days is possible) 0.25/0.526 = 0.48 days
- Now if the interest that can be earned reduces to 4%, the average daily interest will also reduce to $0.263. At this level, the time required to cover the cost should reduce by 0.95 days
The difference is simply because the opportunity cost in terms of alternate usage of funds has decreased for the company.
Answer:
The profit that they keep to reinvest in the business is recorded as D : retained earnings.
Explanation:
Retained earnings (RE) is the amount of net income left over for the business after it has paid out dividends to its shareholders.
Answer:
a. Salary for the second year:
Salary is to increase by 4% in second year.
= 53,000 * (1 + 4%)
= $55,120
b. Third year salary:
Second year salary will increase by 5.5%
= 55,120 * (1 + 5.5%)
= $58,151.60
c. Fourth year salary:
Third year salary to increase by 11.1%
= 58,151.60 * (1 + 11.1%)
= $64,606.43
Answer:
<em>The answer is 17.01 minutes</em>
Explanation:
<em>Given that:</em>
<em>The learning rate (r) = 85% = 0.85</em>
<em> T₃₂= 23.52 minutes</em>
<em>By applying the learning curve formula</em>
<em>Thus,</em>
<em>Tₙ = T₁ nᵇ</em>
<em>Where b represent ln(r)/ln2</em>
<em>b = ln( 0.85)/ln2 = -0.2344</em>
<em>23.55 = T₁ * (32)^-0.2344</em>
<em>T₁ = 23.55 * (32)^0.2344</em>
<em>Now,</em>
<em>T₁₂₈ = T₁ (128)^ - 0.2344</em>
<em>= 23.55 * (32)^0.2344 * (128)^ - 0.2344</em>
<em>=17.01 minutes</em>
