Answer:
Incomplete question
First aspect of the question is typed below.
The shape of the distribution of the time required to get an oil change at a 20-minute oil-change facility
is unknown. However, records indicate that the mean time is 2l.2-minutes, and the standard deviation 3.5 minutes.
Explanation:
Employees bonus $50
35 oil changes between 10:00 am to 12:00pm
n = 35
10% changes
So, the z - score can be calculated using
z-score = InvNorm(0.10)
z-score = -1.28
So, given that,
Standard deviation is 3.5minutes
σ = 3.5 minutes
Mean time is 21.2 minutes
μx = 21.2 minutes
Then,
σx = σ / √n
σx = 3.5 / √35
σx = 0.5916 minutes
Then, Z score can be written as
Z = (x - μx) / σx
-1.28 = (x - 21.2) / 0.5916
Cross multiply
-1.28 × 0.5916 = x - 21.2
-0.7573 = x - 21.2
x = 21.2 - 0.7573
x = 20.443 minutes
There is a 10% chance of being at or below a mean oil-change time of 20.44 minutes
Answer:
getting car insurance is the correct answer.
Explanation:
Answer:
(a) 0.0085 rugs per dollar.
(b) 0.0069 rugs per dollar.
Explanation:
We have been given that Hokey Min's Kleen Karpet cleaned 75 rugs in October, consuming the following resources: Labor: 520 hours at $17 per hour.
(a) To find the labor productivity per dollar, we will divide number of rugs by amount spent on labor.




Therefore, the labor productivity is 0.0085 rugs per dollar.
(b) To find the multi-factor productivity, we will divide number of rugs by total cost or expenses.








Therefore, the multi-factor productivity is 0.0069 rugs per dollar.
Answer:
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