Answer:
The volume will be 89.6875 ml
Explanation:
So to count this we will use a single proportion.
0.0640 mol - 1000 ml
5.74×10−3 mol - x ml
x ml=5.74×10−3 mol*1000 ml/0.0640 mol=89.6875 ml
Answer:
The final pressure is approximately 0.78 atm
Explanation:
The original temperature of the gas, T₁ = 263.0 K
The final temperature of the gas, T₂ = 298.0 K
The original volume of the gas, V₁ = 24.0 liters
The final volume of the gas, V₂ = 35.0 liters
The original pressure of the gas, P₁ = 1.00 atm
Let P₂ represent the final pressure, we get;



∴ The final pressure P₂ ≈ 0.78 atm.
The molality of the solution is obtained as 0.63 m.
<h3>What is the freezing point?</h3>
The freezing point is the temperature at which the liquid is converted into solid.
We know that;
ΔT = 3.5° C
K = 1.86° C/m
i = 3
m = ?
Thus;
ΔT = K m i
m = ΔT/K i
m = 3.5° C/ 1.86° C/m * 3
m = 0.63 m
Learn more about freezing point:brainly.com/question/3121416
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Your answer is C. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.