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Nadusha1986 [10]
2 years ago
10

(9) Which is true from the following ?

Chemistry
1 answer:
fredd [130]2 years ago
4 0

Answer:

The correct answer is A and D.

Explanation:

Please I want brainliest.

Reason:

The size of the ions follows the order:

Negatively charged ion > Neutral atom >

Positively charged ion

This is because of the size of ions increases when the electrons are added to the outermost shell of an atom.

This happens due to the increase in

electron-electron repulsion.

Moreover, when the electrons are removed from an atom, then the affective nuclear charge that is experienced by the outermost electron increases.

Thus the size of the positively charged ion is least.

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When I2 and FeCl2 are mixed together, iodine (I) cannot replace chlorine (Cl) in the compound because iodine is lower on the per
andrezito [222]

The given statement is True.


This is single replacement reaction.

As reactivity decreases down the group,

Iodine is less reactive than Chlorine.  

And so Iodine cannot replace chlorine from FeCl2.

I2 + FeCl2 ---> no reaction (Iodine is less reactive than chlorine)

7 0
3 years ago
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Compare and contrast absolute and relative dating
svet-max [94.6K]
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What does temperature indirectly measure? 1)Sound 2)Thermometers 3)Chemical Reactions 4)Heat​
attashe74 [19]

Answer:

Heat

Explanation:

Temperature is the average thermal energy (or heat) in a substance. Sound isn't really related, thermometers measure temperature, and chemical reactions can produce heat, but none of those are measured by temperature.

3 0
3 years ago
How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

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