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dalvyx [7]
3 years ago
12

Why is the brcl molecule polar? the shared electrons are closer to cl due to the greater electronegativity of chlorine. bromine

has a large positive nucleus. three-dimensional geometry is asymmetrical. chlorine gains an electron whereas bromine loses one?
Chemistry
2 answers:
klio [65]3 years ago
8 0
The shared electrons are closer to Cl due to the greater electronegativity of chlorine.
Licemer1 [7]3 years ago
5 0

Answer: the shared electrons are closer to cl due to the greater electronegativity of chlorine.


Justification:


1) In a covalent bond (the bond between two non-metal elements) the electrons are shared.


2) When the two elements have different electronegativities the electrons are not evely shared: the element with the greatest electronegativity will pull the electrons with higher strength.


3) As consequence the electrons will be closer to the most electronegative atom creating a dipole moment, which is what causes the molecule to be polar.


4) You can learn the trend of electronegativity in the periodic table: in a group the electronegativity decreases downward. With this you do not need a table with the values of the electronegativities and can predict that the electronegativity of Cl is greater than the electronegativity of Br.


5) From above statements you can conclude that, due to its greater electronegativity, chorine will pull the electrons with greater strength, causing the molecule to be polar.

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4 0
3 years ago
If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4
statuscvo [17]

Answer:

The mass of calcium sulfate that will precipitate is 6.14 grams

Explanation:

<u>Step 1:</u> Data given

500.0 mL of 0.10 M Ca^2+ is mixed with 500.0 mL of 0.10 M SO4^2−

Ksp for CaSO4 is 2.40*10^−5

<u>Step 2:</u> Calculate moles of Ca^2+

Moles of Ca^2+ = Molarity Ca^2+ * volume

Moles of Ca^2+ = 0.10 * 0.500 L

Moles Ca^2+ = 0.05 moles

<u>Step 3: </u>Calculate moles of SO4^2-

Moles of SO4^2- = 0.10 * 0.500 L

Moles SO4^2- = 0.05 moles

<u>Step 4: </u>Calculate total volume

500.0 mL + 500.0 mL = 1000 mL = 1L

<u>Step 5: </u> Calculate Q

Q = [Ca2+] [SO42-]  

[Ca2+]= 0.050 M   [O42-]

Qsp = (0.050)(0.050 )=0.0025 >> Ksp

This means precipitation will occur

<u> Step 6:</u> Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M = Molar solubility

<u> Step 7:</u> Calculate total CaSO4 dissolved

total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 mol/L = 0.667 g

<u>Step 8:</u> Calculate initial mass of CaSO4

Since initial moles CaSo4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

<u>Step 9:</u> Calculate mass precipitate

6.807 - 0.667 = 6.14 grams

The mass of calcium sulfate that will precipitate is 6.14 grams

5 0
3 years ago
If an acid has a ka=1.6x10^-10, what is the acidity of the solution?
LUCKY_DIMON [66]
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
 In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+.  If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
5 0
3 years ago
A certain automobile contains 4 tires, 2 headlights, 1 steering wheel,
Step2247 [10]

Answer:

143 parts I think probably not

5 0
3 years ago
1.
GarryVolchara [31]

Answer:

The value of the Golden Igloo is $227.4 million.

Explanation:

First, we need to find the inner and the outer volume of the half-spherical shell:

V_{i} = \frac{1}{2}*\frac{4}{3}\pi r_{i}^{3}

V_{o} = \frac{1}{2}*\frac{4}{3}\pi r_{o}^{3}

The total volume is given by:

V_{T} = V_{o} - V_{i}

Where:

V_{i}: is the inner volume

r_{i}: is the inner radius = 1.25/2 = 0.625 m

V_{o}: is the outer volume

r_{o}: is the outer radius = 1.45/2 = 0.725 m

Then, the total volume of the Igloo is:

V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3}

Now, by using the density we can find the mass of the Igloo:

m = 19.3 \frac{g}{cm^{3}}*0.29 m^{3}*\frac{(100 cm)^{3}}{1 m^{3}} = 5.60 \cdot 10^{6} g

Finally, the value (V) of the antiquity is:

V = \frac{\$ 1263}{oz}*5.60 \cdot 10^{6} g*\frac{1 oz}{31.1034768 g} = \$ 227.4 \cdot 10^{6}  

Therefore, the value of the Golden Igloo is $227.4 million.

I hope it helps you!  

8 0
2 years ago
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