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loris [4]
3 years ago
15

A block of metal has a mass of 18.361kg and the following dimensions: 22.35 cm x 7.34 cm x 22.05 mm. What is the density of the

metal in g/cm^3
Chemistry
1 answer:
professor190 [17]3 years ago
3 0

Answer:

50.76 g/cm³

Explanation:

We'll begin by converting 18.361 Kg to g. This can be obtained as follow:

1 Kg = 1000 g

Therefore,

18.361 Kg = 18.361 Kg × 1000 g / 1 Kg

18.361 Kg = 18361 g

Next, we shall express the dimension in the same unit of measurement.

Dimension = 22.35 cm x 7.34 cm x 22.05 mm

Thus, we shall convert 22.05 mm to cm. This can be obtained as follow:

10 mm = 1 cm

Therefore,

22.05 mm = 22.05 mm × 1 cm / 10 mm

22.05 mm = 2.205 cm

Thus, the dimension is 22.35 cm x 7.34 cm x 2.205 cm.

Next, we shall determine the volume of the metal. This can be obtained as follow:

Dimension = 22.35 cm x 7.34 cm x 2.205 cm.

Volume = 361.728045 cm³

Finally, we shall determine the density of the metal. This can be obtained as follow:

Mass of metal = 18361 g

Volume of metal = 361.728045 cm³

Density of metal =?

Density = mass / volume

Density of metal = 18361 / 361.728045

Density of metal = 50.76 g/cm³

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                   2) (<em>cis</em>)-but-2-ene

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b) Balance Equation:

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As H₃PO₄ is catalyst and remains unchanged so we can also write as,

                                    C₄H₁₀O   →   C₄H₈ + H₂O

c) Rule:

           When more than one alkene products are possible then the one thermodynamically stable is favored. Thermodynamically more substituted alkenes are stable. Furthermore, trans alkenes are more stable than cis alkenes. Hence, in our case the major product is trans alkene followed by cis. The minor alkene is the 1-butene as it is less substituted.

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Answer:

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Explanation:

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By using Arrhenius equation at two different two different temperature,

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E_a=5510.265cal/mole;

By rounding off upto 2 significant figure;

E_a=5.5Kcal/mole;

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