Answer:
The answer is "Choice A and Choice B"
Explanation:
The Zero-Order reactions are usually found if a substrate, like a surface or even a catalyst, is penetrated also by reactants. Its success rate doesn't depend mostly on the amounts of the various reaction in this reaction.
Let the Rate = k
As
doesn't depend on reaction rate, a higher reaction rate does not intensify the reaction.
By the rate
the created based and the reaction rate is about the same.
Answer:
Weight of element X = 14.01 gram
Explanation:
Mass percentage is calculated by using :
![Percent =\frac{Mass\ of\ element}{Total\ mass}\times 100](https://tex.z-dn.net/?f=Percent%20%3D%5Cfrac%7BMass%5C%20of%5C%20element%7D%7BTotal%5C%20mass%7D%5Ctimes%20100)
![O\ Percent=\frac{Mass\ of\ O}{Total\ mass\ of\ XO2}\times 100](https://tex.z-dn.net/?f=O%5C%20Percent%3D%5Cfrac%7BMass%5C%20of%5C%20O%7D%7BTotal%5C%20mass%5C%20of%5C%20XO2%7D%5Ctimes%20100)
Mass of O = 16.0 gram
let mass of X = X grams = ?
Mass of XO2 = mass of X + 2(mass of O)
Mass of XO2 = X + 2(16)
Mass of XO2 = X + 32
Total mass of O in the compound = 2(16) = 32 grams
Percent O = 69.55 %
![Percent\ O =\frac{Mass\ of\ O}{Total\ mass\ of\ XO2}\times 100](https://tex.z-dn.net/?f=Percent%5C%20O%20%3D%5Cfrac%7BMass%5C%20of%5C%20O%7D%7BTotal%5C%20mass%5C%20of%5C%20XO2%7D%5Ctimes%20100)
![69.55=\frac{32}{X+32}\times 100](https://tex.z-dn.net/?f=69.55%3D%5Cfrac%7B32%7D%7BX%2B32%7D%5Ctimes%20100)
![\frac{69.55}{100}=\frac{32}{X+32}](https://tex.z-dn.net/?f=%5Cfrac%7B69.55%7D%7B100%7D%3D%5Cfrac%7B32%7D%7BX%2B32%7D)
![0.6955=\frac{32}{X+32}](https://tex.z-dn.net/?f=0.6955%3D%5Cfrac%7B32%7D%7BX%2B32%7D)
![0.6955\times (X+32)=32](https://tex.z-dn.net/?f=0.6955%5Ctimes%20%28X%2B32%29%3D32)
![0.6955X+ 22.256=32](https://tex.z-dn.net/?f=0.6955X%2B%2022.256%3D32)
![0.6955X=9.744](https://tex.z-dn.net/?f=0.6955X%3D9.744)
![X=\frac{9.744}{0.6955}](https://tex.z-dn.net/?f=X%3D%5Cfrac%7B9.744%7D%7B0.6955%7D)
![X =14.01](https://tex.z-dn.net/?f=X%20%3D14.01)
weight of element X = 14.01 gram
14.01 is mass of nitrogen N
The correct formula of this element is NO2
Atomic number = 18 (Number of protons)
Mass number = 18 + 20 (Number of protons + neutrons)
6 Carbon atoms
18 Oxygen atoms
12 Hydrogen atoms