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AnnyKZ [126]
4 years ago
5

According to the MSDS, which best describes propane?

Chemistry
1 answer:
Mrac [35]4 years ago
4 0
Propane, a colourless, easily liquefied, gaseous hydrocarbon (compound of carbon and hydrogen), the third member of the paraffin series following methane and ethane. The chemical formula for propane is C3H8. It is separated in large quantities from natural gas, light crude oil, and oil-refinery gases and is commercially available as liquefied propane or as a major constituent of liquefied petroleum gas (LPG).


As with ethane and other paraffin hydrocarbons, propane is an important raw material for the ethylene petrochemical industry. The decomposition of propane in hot tubes to form ethylene also yields another important product, propylene. From propylene such organic chemicals as acetone and propylene glycol are derived. The oxidation of propane to such compounds of carbon, hydrogen, and oxygen as acetaldehyde is also of commercial interest.

Although a gas at ordinary atmospheric pressure, propane has a boiling point of -42.1° C (−43.8° F) and thus is readily liquefied under elevated pressures. It therefore is transported and handled as a liquid in cylinders and tanks. In this form, alone or mixed with liquid butane, it has great importance as a fuel for domestic and industrial uses and for internal-combustion engines.

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You might be interested in
How much heat does it take to raise 100g of aluminum (c= .9 J/gC) from 12.5C to 31C?
zlopas [31]

Answer:

When two substances having different temperatures are introduced or kept together, heat energy, Q, flows from a substance at higher temperature to a substance at lower temperature. Also, heat continues to be transferred until their temperatures are equalized, at which point the substances are in thermal equilibrium. In a closed system, the amount of energy lost is equal to but opposite the amount of energy gained.

Explanation:

5 0
3 years ago
At what celsius temperature does 0.750mol of an ideal gas occupy a volume of 35.9L at 114kPa
pashok25 [27]

Answer:

378.25°C

Explanation:

Given data:

Number of moles of gas = 0.750 mol

Volume of gas = 35.9 L

Pressure of gas = 114 KPa (114/101 = 1.125 atm)

Temperature of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

now we will put the values.

T = PV/nR

T = 1.125 atm × 35.9 L /0.750 mol  × 0.0821 atm.L/ mol.K

T = 40.3875/0.062/K

T = 651.4 K

Kelvin to °C:

651.4 K - 273.15 = 378.25°C

8 0
4 years ago
The pH of a solution is 8.83±0.048.83±0.04 . What is the concentration of H+H+ in the solution and its absolute uncertainty?
slava [35]

Answer:

The concentration of H^{+} is 1.48  × 10^{-9} M

The absolute uncertainty of [{H^{+}] is ±0.12 × 10^{-9} M

The concentration of H^{+} is written as 1.48(±0.12) × 10^{-9} M

Explanation:

The pH of a solution is given by the formula below

pH = -log_{10}[{H^{+}]

∴ [H^{+}] = 10^{-pH}

where [{H^{+}] is the H^{+} concentration

From the question,

pH = 8.83±0.04

That is,

pH =8.83 and the uncertainty is ±0.04

First, we will determine [{H^{+}] from

[H^{+}] = 10^{-pH}

[{H^{+}] = 10^{-8.83}

[{H^{+}] = 1.4791 × 10^{-9} M

[{H^{+}] = 1.48 × 10^{-9} M

The concentration of H^{+} is 1.48  × 10^{-9} M

The uncertainty of [{H^{+}]  ( U_{[H^{+}] } ) from the equation [H^{+}] = 10^{-pH} is

U_{[H^{+}] } = 2.303 \\ × {[H^{+}] } × U_{pH }

Where U_{[H^{+}] } is the uncertainty of [{H^{+}]

U_{pH } is the uncertainty of the pH

Hence,

U_{[H^{+}] } = 2.303 × 1.4791 × 10^{-9} × 0.04

U_{[H^{+}] } = 1.36 × 10^{-10} M

U_{[H^{+}] } = 0.12 × 10^{-9} M

Hence, the absolute uncertainty of [{H^{+}] is ±0.12 × 10^{-9} M

6 0
4 years ago
7. Which of the following best describes vinegar?
stepladder [879]
I think the answer is c
6 0
3 years ago
The scientific method typically ends with a ​
kifflom [539]

Answer: Conclusion

Explanation:

After they test the hypothesis they come to a conclusion of the answer.

and sometime test it again and again

7 0
3 years ago
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