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2 years ago

PLEASE HELP URGENT Given \tan \theta =0.6, find the value of b

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

3 0

$\tan(theta ) = \frac{5.3}{b} \\$

$0.6 = \frac{5.3}{b} \\$

$b = \frac{5.3}{0.6} \\$

$b = 8.83 \: \: cm$

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zhenek [66]

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3 years ago

Please help me solve this problem ASAP

MArishka [77]

Use the pythagorean theorem formula: a^2 + b^2 = c^2
c is the longest side of a triangle.
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14^2 + 11^2 = c^2
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6 0

3 years ago

Say that the economy is in an expansion, causing wages to increase by six percent. if you previously received a monthly salary o

GalinKa [24]

The new monthly salary will be $1,457.50.

You received a monthly salary of $1,375.00

Now by economy expansion, causing wages to increase by = 6%

Increment of the salary = 6% of 1,375.00

$= \frac{6}{100} \times 1,375$

$= 0.06 \times 1,375 =\$82.50$

<h3>What is the monthly salary?</h3>

Monthly Salary means Employee's monthly salary, before deductions.

Therefore our new monthly salary would be

$= $1,375.00 + $82.50\\ = $1,457.50$

Therefore our new monthly salary will be $1457.50.

To learn more about the monthly salary visit:

brainly.com/question/24825618

7 0

2 years ago

The mass of a tiger at a zoo is 135 kgs Randy's cat has a mass of 5000gms how many times greater is the mass of the tiger than t

weqwewe [10]

Mass of the cat=5000g =5kg
Hence the tiger is 135/5=27 heavier than the mass of the cat

3 0

3 years ago

The amount of time the husband and the wife spend on house work is measured for 15 women and their 15 husbands. For the wives th

dolphi86 [110]

Answer:

The value of the test statistic is z = -0.877.

Step-by-step explanation:

Testing the difference in mean time spent on housework between husbands and wives.

At the null hypothesis, we test if there is no difference, that is, the subtraction of the means is 0:

$H_0: \mu_H - \mu_W = 0$

At the alternate hypothesis, we test if there is a difference, that is, the subtraction of the means is different from 0.

$H_1: \mu_H - \mu_W \neq 0$

The test statistic is:

$z = \frac{X - \mu}{s}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that $\mu = 0$

For the wives the mean was 7 hours/week and for the husbands the mean was 4.5 hours/week. The standard deviation of the differences in time spent on house work was 2.85.

This means that $X = 4.5 - 7 = -2.5, s = 2.85$

What is the value of the test statistic for testing the difference in mean time spent on housework between husbands and wives?

$z = \frac{X - \mu}{s}$

$z = \frac{-2.5 - 0}{2.85}$

$z = -0.877$

The value of the test statistic is z = -0.877.

4 0

3 years ago