18 and 17 should have a line through
Answer:
For part a)
130 = 10/2[2a+(10-1)d]
Simplify, u get
2a + 9d = 26.................(1)
Also U5 = a + (5-1)d = 3a
Simplify, u get
a= 2d...................(2)
Substituting for a in equation 1,
2(2d)+9d= 26
Solving for d, we get
d = 2
In part b) substituting for d in equation 2 to get the first term
a = 2(2) = 4
Part c) the no. of terms required can be obtained by solving
28 = 4+(n-1)2
n = 13
Answer:
trifi
Step-by-step explanation:
4t3 a good relationship is the same way you could get to the claire family thing you want but I have different feelings about the same way
Let's pick an arbitrary value of 5.




Let's pick another arbitrary value: 1


Between these two values, the polynomial is continuous. This means for the two polynomial points to be satisfied, there must be
at least one root between these two points.
We can either use the Intermediate Value Theorem or Newton's method to make a better approximation from there.