La frecuencia de una onda es 60Hz y su velocidad, 30 m/s. Calcula su longitud de onda
1 answer:
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Answer:
The acceleration of the train is 5 m/s².
Explanation:
Given:
let the initial velocity of a train = 5 m/s and
final velocity of a train = 45 m/s
time taken = 8 s
To find:
acceleration: ?
Solution:
We define acceleration as change in velocity per unit time that is the difference between the final velocity and initial velocity divided by time.
On substituting the above values we get the required acceleration
Therefore,the acceleration of the train is 5 m/s².
Answer:
<em>The shortest distance to an object that this radar can detect would be </em>
<em>111 m</em>
Explanation:
The shortest distance is the minimum distance that would be detected by the radar, The time of oscillation can be obtained thus;
T = 1/f ..........1
but f= v/λ substituting f into equation 1 we have;
T = λ/v...............2
Where λ is the wavelength = 2.2 m
v is the velocity of light since the radar is an electromagnetic wave
= 3 x m/s
T = 2.2 m / 3 x m/s
T = 7.33 x s
<u>Calculating the time interval required by the pulse</u>
Since the interval of the pulse (t) is 100 times greater than the period of oscillation, the time of the pulse is expressed as;
t = 100 x T
t = 100 x 7.33 x s
t = 7.33 x s
Therefor the time of the pulse is 7.33 x s
<u>Calculating for the shortest distance of the radar</u>
The shortest distance of the radar can be obtained using the equation below;
λ_s = (t/2) x v ............3
Substituting into equation 3 we have
λ_s = (7.33 x /2) x 3 x
m/s
λ_s = 111 m
Therefore the shortest distance to an object that this radar can detect would be 111 m