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charle [14.2K]
3 years ago
6

A box of weight 74 N is sliding on a horizontal surface at a constant velocity due to an external force F-> of magnitude 4.8

N. A normal force (n->) and a friction force (f->) also act on the box. What is the magnitude of the friction force?
74 N


2.4 N


69 N


4.8 N


9.6 N

Physics
1 answer:
n200080 [17]3 years ago
6 0

Answer

4.8 N

If the box is moving with a constant velocity, then we can say that the system is in equilibrium. This is because if the external force (F->) was greater than other forces the box would be accelerating. This tells us that this force (F->) is just enough to overcome friction and so it must be equal to 4.8 N.

The normal force has no effect to the horizontal velocities or forces. It is equal to -Weight. That is -74 N. The negative sign shows that the force is in opposite direction.

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Now using formula of effective degree of freedom of mixture, (f), we have: 

f= (f1n1+f2n2)/(n1+n2)
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6 0
3 years ago
If size of an image is 10 cm and the magnification produced by a mirror is +1, what will be the size of object?
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Answer:

h = 10 cm

Explanation:

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So,

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