A box of weight 74 N is sliding on a horizontal surface at a constant velocity due to an external force F-> of magnitude 4.8
N. A normal force (n->) and a friction force (f->) also act on the box. What is the magnitude of the friction force?
74 N
2.4 N
69 N
4.8 N
9.6 N
74 N
2.4 N
69 N
4.8 N
9.6 N
1 answer:
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Answer:
The focal length of the appropriate corrective lens is 35.71 cm.
The power of the appropriate corrective lens is 0.028 D.
Explanation:
The expression for the lens formula is as follows;
Here, f is the focal length, u is the object distance and v is the image distance.
It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.
Put v= -71.4 cm and u= 24.0 cm in the above expression.
f= 35.71 cm
Therefore, the focal length of the corrective lens is 35.71 cm.
The expression for the power of the lens is as follows;
Here, p is the power of the lens.
Put f= 35.71 cm.
p=0.028 D
Therefore, the power of the corrective lens is 0.028 D.
Answer:
Explanation:
<u>Dimensional Analysis</u>
It's given the relation between quantities A, B, and C as follows:
and the dimensions of each variable is:
Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):
Operating:
Equating the exponents:
Adding both equations:
Solving:
Answer: