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3 years ago

7

Explain how elastic force is used to shoot an arrow from a bow.

2 answers:

Hunter-Best [27]3 years ago

5 0

Answer:

The bow bends when the archer pulls back on the string. The bow can bend because it is made of an elastic material. ... Releasing the string thrusts the arrow forward with the elastic force of the bow. The elastic potential energy of the bow is converted to the kinetic energy of the arrow.2 Jan 2014

mash [69]3 years ago

5 0

God does it god knows man

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A car travels initially at 24 m/s, until it enters the highway. If the car accelerates at 4 m/s^2 for a 96 meters, what is the c

marishachu [46]

initial velocity=u=24m/s
Acceleration=a=4m/s^2
Distance=s=96m
Final velocity=v

Using 3rd equation of kinematics

$\boxed{\Large{\sf v^2-u^2=2as}}$

$\\ \Large\sf\longmapsto v^2=u^2+2as$

$\\ \Large\sf\longmapsto v^2=24^2+2(4)(96)$

$\\ \Large\sf\longmapsto v^2=576+768$

$\\ \Large\sf\longmapsto v^2=1344$

$\\ \Large\sf\longmapsto v=\sqrt{1344}$

$\\ \Large\sf\longmapsto v=36.6m/s$

3 0

3 years ago

PLEASE HELP I HAVE NO TIME PLEASEEE DONT SKIP

Triss [41]

2m/s

it has to be 20 charecters just ignore this your answer is up there

7 0

3 years ago

A piece of silicon sample has a resistivity of 0.1 ω.Cm. Its thickness is 100µm. The electron mobility is 1350cm 2 v -1sec-1. Wh

lawyer [7]

The answer is Rh = 135 cm^3 and B = 0.05185 wh/m^2

Explanation:

Resitivity of silicon = 0.1

thickness = 100um

so, I = ma

Required to find out concentration of electron , we know that

Rh = up

By putting in the values,

Rh = 1350 x 0.1

Rh = 135 cm^3

Now consider,

Rh = 1 / Rh.q

= 1 / Rh . q

= 1 / 135 x1.609 x10^-19

= 4.6037 x 10^16 / cm^3

Vh = BIRh / w

B = Vh w/ IRh

B = -70 x10^-6 x 100 x10^-6 / 1x 10^-3 x 135 x 10^-6

B = 0.05185 wh / m^2

5 0

3 years ago

A woman with a mass of 52.0 kg is standing on the rim of a large disk that is rotating at an angular velocity of 0.470 rev/s abo

Charra [1.4K]

Explanation:

It is given that,

Mass of the woman, m₁ = 52 kg

Angular velocity, $\omega=0.47\ rev/s=2.95\ rad/s$

Mass of disk, m₂ = 118 kg

Radius of the disk, r = 3.9 m

The moment of inertia of woman which is standing at the rim of a large disk is :

$I={m_1r^2}$

$I={52\times 3.9^2}$

I₁ = 790.92 kg-m²

The moment of inertia of of the disk about an axis through its center is given by :

$I_2=\dfrac{m_2r^2}{2}$

$I_2=\dfrac{118\times (3.9)^2}{2}$

I₂ =897.39 kg-m²

Total moment of inertia of the system is given by :

$I=I_1+I_2$

$I=790.92+897.39$

I = 1688.31 kg-m²

The angular momentum of the system is :

$L=I\times \omega$

$L=1688.31 \times 2.95$

$L=4980.5\ kg-m^2/s$

So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.

8 0

3 years ago

The density of blood is 2kg/m.convert to g/cm

sertanlavr [38]

Explanation:

if we convert it into g/cm it'll be

2000 grams

6 0

2 years ago