Please help me understand the question

In a survey of 800 people, 42% said they shopped online last week. How many people said they shopped online last week?

slavikrds [6]

336

explanation:

percent. part

_______ = _____

100. whole

42. ?

____ = ____

100. 800

cross multiply

800×42=33,600

then divide by 100

33,600/100=336

3 0

2 years ago

Read 2 more answers

At one gas station, gas costs $2.75 per gallon. Complete the equation that relates the total cost, C, to the number of gallons o

dolphi86 [110]

Answer:

C = 2.75

Step-by-step explanation:

it does not tell how much there for it is 1 gallon

6 0

2 years ago

In a particular game of chance, a wheel consists of 42 slots numbered 00, 0, 1, 2,...,40. To play the game, a metal ball is

Nikolay [14]

Answer:

The sample space for one spin of this game is: S = {00, 0, 1, 2, 3,…, 40}

Step-by-step explanation:

Consider the provided information.

In probability theory, the set of all possible outcomes or outcomes of that experiment is the sample space of an experiment or random trial. Using set notation, a sample space is usually denoted and the possible ordered outcomes are identified as elements in the set.

Here the possible number of elements in the set are 00, 0, 1, 2,...,40

The sample space is anything the ball can land on.

Thus, the sample space for one spin of this game is: S = {00, 0, 1, 2, 3,…, 40}

6 0

3 years ago

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.

Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Step-by-step explanation:

GIven that:

$f(x) = 5e^{-x^2} cos (4x)$

The Maclaurin series of cos x can be expressed as :

$\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+... \ \ \ (1)}$

$\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0} \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!} -\dfrac{x^6}{3!}+... \ \ \ (2)}$