Ask question

Ask question

All categories

2 years ago

12

A rectangular pyramid fits exactly on top of a rectangular prism. The prism has a length of 16 cm, a width of 6 cm, and a height

of 8 cm. The pyramid has a height of 14 cm. Find the volume of the composite space figure.

1 answer:

blondinia [14]2 years ago

3 0

Answer:

<u>1,216 cm³</u>

Step-by-step explanation:

Volume (composite space figure) = Volume (pyramid) + volume (prism)

⇒ [16 x 6 x 14 / 3] + [16 x 6 x 8]
⇒ 96 [14/3 + 8]
⇒ 96 [14/3 + 24/3]
⇒ 96 x 38/3
⇒ 32 x 38
⇒ <u>1,216 cm³</u>

You might be interested in

The height of a man is 1.7.what is his height in centemeters

gulaghasi [49]

He is 51.816 centimeters tall if he is 1.7 feet tall.

4 0

3 years ago

Read 2 more answers

PLEASE HELP ME :) 20 points

Sindrei [870]

Answer:

its d thats the right anwsers

Step-by-step explanation:

6 0

2 years ago

Triangle C D E is rotated 90 degrees to form triangle C prime D prime E prime.

Pavlova-9 [17]

C’D’E’ ... hope it’s right

6 0

2 years ago

Read 2 more answers

original price of a calendar: $14.50 discount: 30% find the new price for the item after the discount

tigry1 [53]

Here, Original price = $14.50
Discount = 30%

Now, Amount of discount = 14.50*0.30 = $4.35

So, price after discount would be: $14.50 - $4.35 = $10.15

Your answer is $10.15

Hope this helps!

5 0

3 years ago

Read 2 more answers

Find the volume of the solid generated by revolving the region bounded by

Rama09 [41]

Answer:

$V =\dfrac{25\pi}{\sqrt{2}}$

Step-by-step explanation:

given,

y=5√sinx

Volume of the solid by revolving

$V = \int_a^b(\pi y^2)dx$

a and b are the limits of the integrals

now,

$V = \int_a^b(\pi (5\sqrt{sinx})^2)dx$

$V =25\pi \int_{\pi/4}^{\pi/2}sinxdx$

$\int sin x = - cos x$

$V =25\pi [-cos x]_{\pi/4}^{\pi/2}$

$V =25\pi [-cos (\pi/2)+cos(\pi/4)]$

$V =25\pi [0+\dfrac{1}{\sqrt{2}}]$

$V =\dfrac{25\pi}{\sqrt{2}}$

volume of the solid generated is equal to $V =\dfrac{25\pi}{\sqrt{2}}$

4 0

3 years ago