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1 answer:
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Answer:
No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer
Step-by-step explanation:
From the graph of the circle
∵ The center of the circle F is at the origin
∴ F is (0 , 0)
∵ The circle passes through point (7 , 0)
- The length of the radius of the circle is the distance between
the center of the circle and a point on the circle
∴ r is the distance between points (0 , 0) and (7 , 0)
∴
∴ The length of the radius of the circle is 7 units
Let us find the distance between point (7 , -7) and the origin (0 , 0)
- If the distance is equal to the radius of the circle, then the point is on the circle
- If the distance is greater than the radius, then the point is outside the circle
- If the distance is less than the radius, then the point is inside the circle
∵ The distance =
∵ r = 7
∵ > 7
∴ The distance is greater than the radius of the circle
∴ Point (7 , -7) lies outside the circle
The correct answer is:
No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle
<em>Your answer is not correct, the correct answer is the 3rd answer</em>
Answer:
a) Average velocity at 0.1 s is 696 ft/s.
b) Average velocity at 0.01 s is 7536 ft/s.
c) Average velocity at 0.001 s is 75936 ft/s.
Step-by-step explanation:
Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by .
To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.
Solution :
a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.
b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.
c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.