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topjm [15]
3 years ago
15

Please help asap !! It’s for a exam and it’s due really soon .

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
4 0
The person above is correct I believe
harina [27]3 years ago
3 0
-6(3x + 1) I’m sure this is it
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What is the gcf of 90,10
e-lub [12.9K]
<span><span>10:   2, 5      </span><span>90:   23, 35      </span><span>GCF:   2  5</span></span>
6 0
3 years ago
Read 2 more answers
Kerry skates laps around the playground.
Zarrin [17]
So to start this off, we need to find the area of the playground. We can simply multiply 150*2 and 50*2, and we get 300 and 100. Add those together and we get 400m.
Now, we can identify the number of laps it takes. But first, we have to convert kilometers into meters. there are 1000 meters in 1 km, so we will use 1000 to find the answer
Now, we can do 1000/400 to find the answer, which is 2.5 
Therefore, it will take Kerry 2.5 laps to skate around the entire park

Answer: 2.5 laps

Hope this helped!!! :D
3 0
4 years ago
Can someone solve this its probably easy but i dont know
Rzqust [24]

Answer:

Step-by-step explanation:

A={26,30,32,44,48}

B={22,26,34}

A∩B=26

number of elements=1

elements in ξ are {22,24,26,28,30,32,34,36,38,40,42,44,46,48}

number of elements  in ξ=14

P(A∩B)=1/14

I can't draw venn diagram but i give hint

A={30,32,44,48}+{26}

B={22,34}+{26}

A∩B={26}

6 0
3 years ago
There are 14 white cabbages and x purple cabbages in a box.
ohaa [14]

Answer:

the angle of a quadrilateral taken in order a× 5× 4× and 2× find these angle draw a rough sketch of the quadrilateral what kind of quadrilateral is it

8 0
2 years ago
Read 2 more answers
In a survey, the planning value for the population proportion is . How large a sample should be taken to provide a confidence in
tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

n random sample taken  (variable of interest)

\hat p=0.35 estimated proportion  (value assumed)

p true population proportion

Confidence =0.95 or 95% (value assumed)

Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.586  

And rounded up we have that n=350

4 0
3 years ago
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