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gizmo_the_mogwai [7]
2 years ago
14

Isabelle runs a restaurant that offers a children's menu. This past week, 20 children ate at her restaurant, and 8 of them order

ed grilled cheese. What is the probability that a randomly selected child eating in Isabelle's restaurant this past week ordered grilled cheese?
Write your answer as a fraction or whole number
Mathematics
1 answer:
kodGreya [7K]2 years ago
8 0
Fraction=8/20 kids ate a grilled cheese at her restaurant in the last week. This simplifies to 2/5. Therefore the probability that a randomly selected child at her restaurant is eating a grilled cheese is 2/5.
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In a study, 8 people ate a total of 1,312 pounds of potatoes in 2 years.
cricket20 [7]

Answer:

83.125 pounds of potatoes

Step-by-step explanation:

1. Divide 1,312 by 2

    1,312/2 = 665

This means that in 1 year 8 people ate 665 pounds of potatoes.

2. Divide 665 by 8

    665/8 = 83.125

This means that in 1 year 1 person ate 83.125 pounds of potatoes.

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Which statement is true about the ratios of squares to circles in the tables? O The ratios in Table A are greater than the ratio
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[B]   The ratios in Table B are greater than the ratios in Table A.

Step-by-step explanation:

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4 years ago
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What is the value of -8 (17-12) over -2(8-(-2))<br><br> A. -4<br> B. -2<br> C. 2 <br> D. 4
Ivan

Answer:

C=2

Step-by-step explanation:

-8(17-12)= -8(5)= -40

then

-2(8-(-2))= -2(10) = -20

so then

-40/-20

=-2

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3 years ago
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Who can help me on my math I’m failing can y’all please help me on some questions.
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Answer:

8 & 17?

Step-by-step explanation:

8*2= 16

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5 0
3 years ago
A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu
yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm,  C2 = 0.0062 m = 0.62 cm

B)  A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = \sqrt[4]{3} is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

f(t) = 10sin(t) N

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speed of mass = 4 cm/s = 0.04 m/s

initial velocity = 3 cm/s = 0.03 m/s

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y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m

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using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)

A) finding the solution of the initial value

attached below is the solution and

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3 years ago
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