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Stella [2.4K]
2 years ago
14

If you divide 42 oranges evenly among 6 people how many oranges will each person have

Mathematics
2 answers:
Goshia [24]2 years ago
5 0

<em><u>42÷6</u></em>

<em><u>=7</u></em>

<u><em>so</em><em> </em><em>each</em><em> </em><em>person</em><em> </em><em>will</em><em> </em><em>have</em><em> </em><em>7</em><em> </em><em>oranges</em><em>.</em></u>

stepan [7]2 years ago
4 0

Answer:

7

Step-by-step explanation:

We have 42 oranges. we want to split the oranges evenly to 6 people. 42 divided by 6 people equals 7 oranges a person.

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Solve for the variable: 2x - 28 = 16
svlad2 [7]
2x = 44
44/2 = x
X= 22
4 0
3 years ago
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The average number of employees that call in sick for the day over the course of a year is 25.
sveta [45]

Answer:

<h3>x¯= 23.8 </h3><h3>μ= 8.2 </h3>

Step-by-step explanation:

<h3>Find the mean. </h3>

 

The mean of a set of numbers is the sum divided by the number of terms.

x¯= <u>25+10+16+39+27+25+32+25+25+22+28+14</u>

                                   11

<h3>Simplify the numerator. </h3>

x¯ = <u>261.27</u>

            11

<h3>Divide  261.27 by 11 </h3>

x¯= 23.75 18

<h3>Divide. </h3>

x¯= 23.75 18

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

x¯=23.8

<h3>Simplify each value in the list. </h3>

25,10,16,39.27,25,32,25,25,22,28,14

Set up the formula for sample standard deviation. The standard deviation of a set of values is a measure of the spread of its values.

s=  n^∑  i=1    √(<u>xi−xavg</u>)²

                            N-1

             

Set up the formula for standard deviation for this set of numbers.

s= ⎷(25−23.8)²+(10−23.8)²+(16−23.8)²+(39.27−23.8)²+(25−23.8)²+<u>(32−23.8)²+(25−23.8)²+(25−23.8)²+(22−23.8)²+(28−23.8)²+(14−23.8)</u>²

                                       11−1

<h3>Simplify the result. </h3>

 

s= √68.05209

The standard deviation should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

8.2

7 0
3 years ago
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A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)
Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}

5 0
3 years ago
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive term
elena55 [62]

Answer:

The no. of variations in sign is 3

Step-by-step explanation:

Variation in sign occurs when every single time a negative product is produced by a pair of consecutive terms.

Therefore, the determination of the number of changes in sign in the given sequence is must.

Therefore, we take the product of the pair of consecutive terms as:

1\times (-3) = - 3, variation in sign

(-3)\times 2 = - 6,  variation in sign

2\times 5 = 10,  no sign variation

5\times (- 4) = - 20,  variation in sign

- 4\times (-6) = 24, no sign variation

7 0
3 years ago
Consider the following functions.G(x) = 4x2; f(x) = 8x(a)
noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form 4x^2+C is an antiderivative of 8x

Step-by-step explanation:

A function <em>F </em>is an antiderivative of the function <em>f</em> if

F'(x)=f(x)

for all x in the domain of <em>f.</em>

(a) If f(x) = 8x, then G(x)=4x^2 is an antiderivative of <em>f </em>because

G'(x)=8x=f(x)

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of <em>f</em>.

(b) Because

\frac{d}{dx}(4x^2)=8x

then G(x)=4x^2 is an antiderivative of f(x) = 8x. Therefore, every antiderivative of 8x is of the form 4x^2+C for some constant C, and every function of the form 4x^2+C is an antiderivative of 8x.

8 0
3 years ago
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