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3 years ago

Calculate the mass in grams of 3. 29 x 104 mol of lithium Help please?

Chemistry

1 answer:

Sedaia [141]3 years ago

3 0

Answer 

no. of moles =

 $\frac{mass \: {g} \: }{ \: molecular \: wight}$ 

so, mass (g)= no. of moles × molecular wight

Explanation:

Li molecular wight equal to 6.941

mass (g)=3.29×104 mol ×6.941 =2374.93g of lithium 

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aksik [14]

Density is mass over volume. If you put it into a formula it would look like this:

$D = \frac{m}{v}$

Based on the problem given, you can see that the mass of the aluminum block is 82.0 g and the volume is 12.8 cm3. Just put that into your equation and solve for it:

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4 years ago

The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.320 M NaOH. What is the init

yan [13]

This question is incomplete, the complete question is;

The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator.

The buret contains 0.320 M NaOH,

It requires 11.2 mL of the NaOH solution to reach the end point of the titration

What is the initial concentration of HCI?

Answer:

initial concentration of HCl is 0.3584 M

Explanation:

Given that;

the reaction between HCl and NaOH is 1:1 molar

HCl(aq) + NaOH(aq) -------> NaCl(aq) + H2O(l)

we know that molarity is the number of moles of solute per liter of solution

so moles of NaOH consumed

= ( 0.320 mol / 1000ml) × 11.2ml

= 0.003584 mol

now

0.003584 moles of NaOH reacts with 0.003584 moles of HCl

moles of HCl present in the 10.0ml solution = 0.003584 mol

therefore the initial concentration of HCl

= ( 0.003584 mol / 10.0ml )× 1000ml

= 0.3584 M

the initial concentration of HCl is 0.3584 M

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Answer:

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