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Otrada [13]
2 years ago
12

If area of cross section of a prism is A cm² and height h cm then find the volume​

Mathematics
1 answer:
AfilCa [17]2 years ago
3 0

Answer:

Volume= area of cross section*height

so, volume of prism = A*h

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The area of a square is increasing at a rate of 24 centimeters squared per second. Find the rate of change of the side of the sq
velikii [3]

Answer:

3cm/s

Step-by-step explanation:

Area of a square is expressed as:

A = L²

Rate of change of area is expressed as:

dA/dt = dA/dL•dL/dt

Given that

dA/dt = 24cm²/s

L = 4cm

Required

dL/dt

Since dA/dl = 2L

dA/dl = 2(4)

dA/dl = 8cm

Subatitute the given values into the formula

24 = 8 dL/dt

dL/dt = 24/8

dL/dt = 3cm/s

8 0
3 years ago
Y = 3 - 5x <br><br><br> solve for x
boyakko [2]

Answer:

x = -1/5y + 3/5

Step-by-step explanation:

y = 3 - 5x

Subtract 3 from both sides;

y - 3 = -5x

Divide both sides by -5

-1/5y + 3/5 = x

4 0
2 years ago
The Human Resources manager at a company records the length
luda_lava [24]

Answer:

the correct answer is 0.84

give brainliest plzzz

6 0
3 years ago
Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g
Ilia_Sergeevich [38]

a. The \vec k component tells you the particle's height:

3t=16\implies t=\dfrac{16}3

b. The particle's velocity is obtained by differentiating its position function:

\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k

so that its velocity at time t=\frac{16}3 is

\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k

c. The tangent to \vec r(t) at t=\frac{16}3 is

\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t

4 0
2 years ago
Solve the following quadratic by<br> completing the square.<br> y = x2 - 6x + 7
kobusy [5.1K]

Answer:

x = 5  or   x = 1

Step-by-step explanation:

 x² - 6x + 7 = 0

x² - 6x = -7

x² - 6x + 9 = -7 + 9      1/2 of the x term than square it and add it the both sides.

(x - 3)(x - 3) = 2

( x -3)² = 2

\sqrt{(x - 3)^2 = \sqrt{2}

(x -  3) = ± 2

x - 3 = 2  or  x - 3 = -2

x = 5     or  x = 1

7 0
2 years ago
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