Question

Find BC in angle ABC Round to the nearest tenth. BC=?

Answer 1

Answer:

BC ≈ 18.7

Step-by-step explanation:

using the sine rule in Δ ABC

$\frac{BC}{sinA}$ = $\frac{AC}{sinB}$ ( substitute values )

$\frac{BC}{sin67}$ = $\frac{20}{sin80}$ ( cross- multiply )

BC × sin80° = 20 × sin67° ( divide both sides by sin80° )

BC = $\frac{20sin67}{sin80}$ ≈ 18.7 ( to the nearest tenth )