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Arlecino [84]
2 years ago
10

Why does benzocaine precipitate during neutralization?.

Chemistry
1 answer:
Natalija [7]2 years ago
5 0

Explain why benzocaine precipitates during the neutralization.

With the addition of an acid, the amine group on the benzocaine will become protonated. The protonation creates a positive charge on the benzocaine molecule. Because of this, benzocaine will become soluble in a polar solvent. However, when the solution is returned to a more basic pH level, the amine will no longer be protonated. Thus, the benzocaine will no longer be soluble and will precipitate during neutralization.

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Which of these boxes will not accelerate?
love history [14]

Answer:

B as all the forces cancel out

Explanation:

20-20=0

25-25=0

3 0
3 years ago
Explain the connection between reactants, products and limiting reactant.
balu736 [363]
In easy words the connection between Reactants, Products and Limiting reactants is as follow,

Reactants and Products:
                                       Reactants are the starting materials for the synthesis of final synthesized materials called as products.

Example:
                 CH₄  +  2 O₂     →      CO₂  +  2 H₂O

In above reaction Methane (CH₄) and Oxygen (O₂) are the reactants while, CO₂ and H₂O are the products.

Reactants, Products and Limiting Reactants:
                                                                       Considering the same example it is seen that for one mole of CO₂ two moles of O₂ are required to completely convert into CO₂ and H₂O. If either of the reactant is taken less than the required amount then it will act as a limiting reactant because it will consume first leaving the second reactant present in excess as compare to it. Hence, we can say that the limiting reactant is the starting material which controls the amount of product being formed.
4 0
3 years ago
Which is the correct complete ionic equation for the reaction of
cricket20 [7]

Answer:

b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

Explanation:

The equation is given as;

2HCl(aq) + Zn(s) + H2(g) + ZnCl2(aq)

In writing an ionic equation, only the aqueous compounds dissociates into ions. This means HCl and ZnCl2 would dissociate to form ions.

This is given as;

2H+  +  2Cl-  + Zn(s) --> H2(g) + Zn2+  + 2Cl-

The correct option is;

b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

8 0
3 years ago
Help please I don’t understand this at all
Paladinen [302]
I think you must do dot and cross diagrams but im not sure at all
7 0
3 years ago
Read 2 more answers
Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
coldgirl [10]

Answer:

\rm_{90}^{231}\text{Th}

Explanation:

The unbalanced nuclear equation is

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + X

Let's write X as a nuclear symbol.

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

235 = 4 + A , so A = 235 - 4 = 231, and

 92 = 2 + Z , so  Z =   92 - 2 =  90

And your nuclear equation becomes

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} +\, _{90}^{231}\text{X}

Element 90 is thorium, so  

\rm X = _{90}^{231}\text{Th}

7 0
3 years ago
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