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3 years ago

Why is litmus paper an example of an indicator

Chemistry

1 answer:

Alexxx [7]3 years ago

5 0

It gives visible feedback based on whether the substance being checked is an acid or an alkali

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Part B When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 22.8 g of carbon were burned in the pres

aksik [14]

Answer: The amount of carbon dioxide gas produced in the reaction is 83.6 grams

Explanation:

As, some amount of oxygen gas is left after the reaction is completed. So, it is present in excess and is considered as an excess reagent.

Thus, carbon is considered as a limiting reagent because it limits the formation of product.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of carbon = 22.8 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

$\text{Moles of carbon}=\frac{22.8g}{12g/mol}=1.9mol$

The chemical equation for the reaction of carbon and oxygen gas follows:

$C+O_2\rightarrow CO_2$

By Stoichiometry of the reaction:

1 mole of carbon produces 1 mole of carbon dioxide gas

So, 1.9 moles of carbon will produce = $\frac{1}{1}\times 1.9=1.9moles$ of carbon dioxide gas

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 1.9 moles

Putting values in equation 1, we get:

$1.9mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(1.9mol\times 44g/mol)=83.6g$

Hence, the amount of carbon dioxide gas produced in the reaction is 83.6 grams

6 0

3 years ago

What is Gallium Nitrite

olganol [36]

It is a binary direct bandgap semiconductor commonly used in light-emitting diodes since the 1990s

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME!!!! Brainiest to the first person to get it right

Nastasia [14]

A: Endoplasmic Reticulum, Chloroplasts

Hoped this helped have a nice day

5 0

3 years ago

Read 2 more answers

If anybody wanna be friends drop your snap below

juin [17]

Cmon bro you better then this

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3 years ago

A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4

Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of iron = 560 J/(kg.K)

$c_1$ = specific heat of water = 4186 J/(kg.K)

$m_1$ = mass of iron = 825 g

$m_2$ = mass of water = 40 g

$T_f$ = final temperature of water and iron = ?

$T_1$ = initial temperature of iron = $352^oC=273+352=625K$

$T_2$ = initial temperature of water = $20^oC=273+20=293K$

Now put all the given values in the above formula, we get:

$(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)$

$T_f=537.12K$

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0

3 years ago