To solve this question, we will use Graham's law which states that:
(R1 / R2) ^ 2 = M2 / M1 where
R1 and R2 are the rates of effusion and M1 and M2 are the molar masses of the two gases.
From the periodic table, we can calculate the molar mass of O2 as follows:
molar mass of O2 = 2*16 = 32 grams
Therefore we have:
R1 / R2 = Ry / RO2 = 1/2
M1 is My we want to get
M2 is molar mass of O2 = 32 grams
Substitute in the above equation to get the molar mass of y as follows:
(1/2) ^2 = (32/My)
1/4 = 32/My
My = 32*4 = 128
Therefore, molar mass of gas y = 128 grams
Answers;
F3S2 Name: Iron Disulfide
Lead(II) nitrate formula: Pb(NO3)2
Silicon tetrafluoride formula: SiF4
Active Transport: Moves ions and molecules from lower to higher concentrations using energy.
Passive Transport: Move ions and molecules from high to lower concentrations without using energy.
The main difference is one uses ATP (energy) and the other does not.
A molecule has an empirical formula of ch, and its molar mass is known to be 26 g/mol and the molecular formula is C₂H₂ ethyne
Molecular formula of compound is (CH)n and the given molar mass is 26g/mol
Molar mass of (CH)n, C=12=n(12+1)=13n
So 13n and n=2
=13×2=26 and given molar mass is also 26g/mol
So here two carbon and two hydrogen so molecular formula is C₂H₂ and name is ethyne
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