I'm assuming the equation is x^3 = 216 or

(both mean the same thing)
If so, then the solution to x^3 = 216 is
x = 6
<span>We can find this by taking the cube root of both sides
</span>x^3 = 216
x = 216^(1/3) .... 1/3 power means cube root
x = 6
Checking the answer:
x^3 = 216
6^3 = 216
6*6*6 = 216
216 = 216
Answer is confirmed
So once again
the answer is x = 6. This is assuming the initial assumption made at the top of the problem holds up.
Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :

For a square , 
⇒ 
⇒ 
⇒ 
⇒ 
Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Answer:
x < -6
Step-by-step explanation:
-4x - 5 > 19
+5 +5
-------------------
-4x > 24
/-4 /-4
-------------------
x < -6
Answer:
b x 390 =339
Step-by-step explanation: