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rodikova [14]
2 years ago
7

Please help out asap thanks

Mathematics
1 answer:
Jet001 [13]2 years ago
6 0

Answer:

there all below

Step-by-step explanation:

Mean: 51.5

There is no mode so you would put "No mode.''

Median: 51

hope this helps <33

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Turn 4 1/6 into an improper fraction.
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now we have: 25/6 divided by 1/5
The rule for dividing is skip the first number, flip the second number, and multiply instead of divide.
So now we have: 25/6 x 6/1 = (25*6)/(6*1) = ?
You must get the final answer yourself. ;-)
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Answer:

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Read 2 more answers
Match each differential equation to a function which is a solution.
inessss [21]

Answer: 1 - C

2 - E

3 - no answer

4 - B

Step-by-step explanation:

A. y = 3x+x^2

y' = 3 + 2x\\y'' = 2

  • Replace in 1:

y'' + y = 0

2 + 3x + x^2 \neq 0

So, A is not an answer for 1

  • Replace in 2:

y' = 3y

3+2x = 3(3x + x^2)

So, A is not an answer for 2

  • Replace in 3

2x^2y'' + 3xy'= y

2x^2(2) + 3x(3 + 2x) = 4x^2 + 9x + 6x^2 \neq 3x+x^2

So, A is not an answer for 3

  • Replace in 4

y'' + 6y' + 8y = 0

2 + 6(3+2x)+8(3x + x^2) = 2+18+12x+24x+8x^2 \neq 0

So, A is not an answer for 4

B. y = e^{-4x}

y' = -4e^{-4x}

y'' = 16e^{-4x}

  • Replace in 1

y'' + y = 0

16e^{-4x} -4e^{-4x} = 12e^{-4x} \neq 0

So, B is not an answer for 1

  • Replace in 2

y' = 3y

-4e^{-4x} \neq 3e^{-4x}

So, B is not an answer for 2

  • Replace in 3

2x^2y'' + 3xy' = y

2x^2(16e^{-4x}) +3x(-4e^{-4x}) \neq  e^{-4x}

So, B is not an answer for 3

  • Replace in 4

y'' + 6y' +8y = 0

16e^{-4x} + 6(-4e^{-4x}) + 8e^{-4x} = e^{-4x}(16-24+8) = 0

So, B is an answer for 4

C. y = sin(x)

y' = cos(x)

y'' = -sin(x)

  • Replace in 1

y'' + y = 0

-sin(x) + sin(x) = 0

So, C is an answer for 1

We jump to

D. y = x^{12}

y' = 12x^{11}

y'' = 132 x^{10}

  • Replace in 2

y' = 3y

12x^{11} \neq 3x^{12}

So, D is not an answer for 2

  • Replace in 3

2x^2y'' + 3xy' = y

2x^2(132x^{10}) + 3x(12x^{11}) = 300x^{12} \neq x^{12}

So, D is not an answer for 3

E. y = 6e^{3x}

y' = 18e^{3x}

y'' = 54e^{3x}

  • Replace in 2

y' = 3y

18e^{3x} = 3(6e^{3x}) = 18e^{3x}

So, E is an answer for 2

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How to simplify 2mg x 5m²k​
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hey, I'm not sure about this answer, but I think it's true, sorry

m(2g+5mk)

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