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1 year ago

7

Please help out asap thanks

1 answer:

Jet001 [13]1 year ago

6 0

Answer:

there all below

Step-by-step explanation:

Mean: 51.5

There is no mode so you would put "No mode.''

Median: 51

hope this helps <33

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What are the steps to solve √(0.2)^(−2)?<br><br>(The answer is 5)

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$\bf 0.\underline{2}\implies \cfrac{02}{1\underline{0}}\implies \stackrel{simplified}{\cfrac{1}{5}} \\\\[-0.35em] ~\dotfill\\\\ \left( \sqrt{0.2} \right)^{-2}\implies \left( \sqrt{\cfrac{1}{5}}\right)^{-2}\implies \left( \sqrt{\cfrac{5}{1}}\right)^{+2}\implies \cfrac{(\sqrt{5})^2}{(\sqrt{1})^2}\implies \cfrac{\sqrt{5^2}}{\sqrt{1^2}}\implies 5$

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Solve the system of linear equations by elimination x + 2y = 13 --x+y=5

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Answer:

{x,y} = {1,6} Have a great day

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2 years ago

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Solve the following system of equations for a and for b:

viktelen [127]

Answer:

$a=3\\b=1$

Step-by-step explanation:

$9a+3b=30\\8a+4b=28$

Let's solve the second equation for a to later on replace it in the first equation.

$8a+4b=28\\8a=28-4b\\a=\frac{28-4b}{8}$

Now plug this into the first equation.

$9a+3b=30\\9(\frac{28-4b}{8})+3b=30$

Distribute the 9

$(\frac{252-36b}{8}) +3b=30$

Break down the fraction.

$\frac{252}{8}-\frac{36b}{8}+3b=30$

Simplify.

$\frac{63}{2}-\frac{9}{2}b+3b=30$

Subtract $\frac{63}{2}$

$-\frac{9}{2}b+3b=30-\frac{63}{2}$

Combine like terms.

$\frac{-9+2*3}{2}b=\frac{30*2-63}{2}$

$\frac{-9+6}{2}b=\frac{60-63}{2}$

$\frac{-3}{2}b=\frac{-3}{2}$

Muliply by the reciprocal or inverted fraction next to b.

$(-\frac{2}{3})(-\frac{3}{2}) b=-\frac{3}{2}(-\frac{2}{3})$

$b=1$

Now plug this value into any of the equations to find the value of a.

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3 years ago

Use the expression to complete the statements. (0.5)10 (0.5)10 is the . (0.5) is the of (0.5)10. 10 is the of (0.5)10. A power i

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Question:

Use the expression to complete the statements.

$(0.5)^{10\\$

________ is the power .

(0.5) is the ________

A ______ is another way to write

Answer:

0.5 is the base

10 is the power

$(0.5)^{10\\ = (\frac{1}{2})^{10}$ -- another way to write

Step-by-step explanation:

Given

$(0.5)^{10\\$

Required

Fill ion the gaps

$(0.5)^{10\\$ is pronounced as; 0.5 raise to the power of 10

From the above statement, we can deduce the following:

0.5 is the base

10 is the power

Lastly, another way to write $(0.5)^{10\\$

Express 0.5 as a fraction

$(\frac{5}{10})^{10}$

Simplify the fraction

$(\frac{5/5}{10/5})^{10}$

$(\frac{1}{2})^{10}$

Hence:

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