Answer:
the x^2 column would have a "22" between the 4 & 5
Step-by-step explanation:
x x^2
0 0
1 1
2 4
3 9
4 16
5 25
6 36
SA = 2lw + 2lh + 2hw
SA = 2(15)(2) + 2(15)(6) + 2(6)(2)
SA = 60 + 180 + 24
SA = 264
if the diameter is 15, its radius is half that, or 7.5
![\bf \textit{area of a circle}\\\\A=\pi r^2~~\begin{cases}r=radius\\[-0.5em]\hrulefill\\r=7.5\end{cases}\implies A=\pi 7.5^2\implies A=56.25\pi \\\\\\A\approx 176.71459\implies A = \stackrel{\textit{rounded up}}{177}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5CA%3D%5Cpi%20r%5E2~~%5Cbegin%7Bcases%7Dr%3Dradius%5C%5C%5B-0.5em%5D%5Chrulefill%5C%5Cr%3D7.5%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%207.5%5E2%5Cimplies%20A%3D56.25%5Cpi%20%5C%5C%5C%5C%5C%5CA%5Capprox%20176.71459%5Cimplies%20A%20%3D%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B177%7D)
Answer:
The percent values were written incorrectly in the equation.
The amount of 7% solution should be written as 1 – x, not x – 1.
Step-by-step explanation:
a and b
