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2 years ago

Can anyone solve this correctly?

Mathematics

1 answer:

andrew-mc [135]2 years ago

3 0

Answer:

A. $200.96 \: {ft}^{2}$

Step-by-step explanation:

Corral is circular in shape.

Radius of the corral would be be the distance from the post to the edge of the corral.

-> r = 8 ft

$A(grass\: eaten) = \pi {r}^{2} \\ \\ = 3.14 {(8)}^{2} \\ \\ = 200.96 \: {ft}^{2}$

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All my question are about math and this test determines my high school classes help if you can please

Mashcka [7]

Answer:

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Step-by-step explanation:

When x = 0, y =2

So, y = 0 + m

2 = 0 + m

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y = x + m

3 = x + 2

-2 -2

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2 years ago

Hose is 32 feet long 32 feet long it needs to be cut into pieces equaling 5’3” How many whole pieces can be cut into how many wh

luda_lava [24]

Answer:

Step-by-step explanation:

Question tests the ability to get quotient

Here, 32 ft is divided by 5’3”

Normally, ft is denoted by ' while inches is denoted by ". So we divide 32 ft by 5ft and 3 inches

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The total is now 5.25'

Now

32'÷5.25'=6.1538461538461

This means, we shall obtain 6 whole pieces with some remainder. Since the question needs the whole pieces only, then the answer is 6

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3 years ago

Simplify (Are all division) 2+4i 3i 3+2i 4+i 2i^11

Alla [95]

$We\ know:\ i=\sqrt{-1}\to i^2=-1$

$\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i$

$\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i$

$2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i$

$Used:\ (a+b)(a-b)=a^2-b^2$

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3 years ago

3x^2 + 4x = -8 solve using quadratic formula

Firdavs [7]

Use the quadratic equation to solve this (image of the quadratic equation is below)

Remember that quadratic functions are set up like so:

$ax^{2} +bx +c = 0$

To make the equation 3x² + 4x = -8 into a quadratic function you must bring -8 to the left side of the equation so it equals zero. To do this add 8 to both sides

3x² + 4x + 8= -8 + 8

3x² + 4x + 8 = 0

That means that in this equation...

a = 3

b = 4

c = 8

^^^Plug these numbers into the quadratic equation and solve (Keep in mind that +/- is ± )

$\frac{-4+/-\sqrt{(4)^{2}-4(3)(8)}}{2(3)}$