Answer:
{0,9,2,-3}
Step-by-step explanation:
the range is all the ys.
these are all in the format (x, y)
Hope this helps.
PS-If it's a multiple choice question, the numbers might not be in the same order. just pick the one with those numbers.
Ac=4 bx=y+4 doesn't make sense. Perhaps you meant <span>Ac-4bx=y+4. If this is not correct, ensure that you have copied down the original problem correctly.
</span>To solve Ac-4bx=y+4 for y, subtract 4 from both sides of this equation. You'll get:
Ac-4bx-4 = y+4 - 4, or y = ac-4bx - 4.
Answer:
6.83 units
Step-by-step explanation:
Let the height of the original pyramid be represented by h. Then the cut off top has a height of (h -2). The scale factor for the area is the square of the scale factor for height, so we have ...
(height ratio)^2 = 1/2
((h -2)/h)^2 = 1/2
(h -2)√2 = h . . . . . . square root; multiply by h√2
h(√2 -1) = 2√2 . . . . add 2√2 -h
h = (2√2)/(√2 -1) ≈ 6.8284 . . . units
The altitude of the original pyramid is about 6.83 units.
Answer:
Part 1) 
Part 2) 
Part 3) m∠K=61°
Part 4) m∠L=119°
Part 5) m∠M=61°
Step-by-step explanation:
we know that
In a parallelogram opposite angles and opposite sides are congruent and consecutive angles are supplementary
Part 1) Find the side MN
we know that
MN≅KL ----> by opposite sides
we have
therefore
Part 2) Find the side KN
we know that
KN≅LM ----> by opposite sides
we have
therefore
Part 3) Find the measure of angle K
we know that
m∠K+m∠N=180° ----> by consecutive interior angles
we have
m∠N=119°
substitute
m∠K+119°=180°
m∠K=180°-119°
m∠K=61°
Part 4) Find the measure of angle L
we know that
m∠L≅m∠N ----> by opposite angles
we have
m∠N=119°
therefore
m∠L=119°
Part 5) Find the measure of angle M
we know that
m∠M≅m∠K ----> by opposite angles
we have
m∠K=61°
therefore
m∠M=61°
The answer would be A = 54raiz (3) + 18raiz (91)
Formula:
A = Ab + Al Where, Ab=base area A= lateral area
The area of the base is: Ab = (3/2) * (L ^ 2) * (root (3)) Where, L= side of the hexagon. Substitute: Ab = (3/2) * (6 ^ 2) * (root (3)) Ab = (3/2) * (36) * (root (3)) Ab = 54raiz (3)
The lateral area is: Al = (6) * (1/2) * (b) * (h) Where, b= base of the triangle h= height of the triangle Substitute: Al = (6) * (1/2) * (6) * (root ((8) ^ 2 + ((root (3) / 2) * (6)) ^ 2)) Al = 18 * (root (64 + 27)) Al = 18raiz (91)
The total area is: A = 54raiz (3) + 18raiz (91)
