Multiplying both sides by
gives

so that substituting
and hence
gives the linear ODE,

Now multiply both sides by
to get

so that the left side condenses into the derivative of a product.
![\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E3v%5D%3D3x%5E2)
Integrate both sides, then solve for
, then for
:




![\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D%5Csqrt%5B3%5D%7B1%2B%5Cdfrac%20C%7Bx%5E3%7D%7D%7D)
Answer:
2. ΔABC is isosceles
Step-by-step explanation:
Given : m∠A = 50
m∠BCD = 180 - (m∠BDC + m∠DBC)
= 180 - (100 + 30)
= 50
then
m∠A = m∠BCD
therefore ΔABC is isosceles
4^3= 64
2^6= 64
Therefore, n=6.
You can also figure this out if you know that 2^3*2^6=2^9. When you multiply exponents with the same base, add the exponents. 3+6=9
Final answer: n=6
Answer:
(x) = 2(1/6)^x
Step-by-step explanation:
To easily solve this problem, we can graph each option using a graphing calculator, or any equation plotting tool.
Case 1
f(x) = 2(6)^x
Case 2
f(x) = 1/2*(6)^x
Case 3
f(x) = 2(1/6)^x
Case 4
f(x) = 1/2*(1/6)^x
By looking at the pictures below, we can tell that the correct option is
Case 3
f(x) = 2(1/6)^x
Since the stretch is done by a factor of 2
2x²(a-b) + x(b-a) + 6(b-a) = 2x²(a-b) - x(a-b) - 6(a-b) = (a-b)(2x²- x - 6)=
=(a-b)(2x+3)(x-2)
6x²(a-b) + x(a-b) + 12(b-a) = 6x²(a-b) + x(a-b) - 12(a-b) =(a-b)(6x²+x - 12)=
=(a-b)(3x - 4)(2x + 3)