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Harlamova29_29 [7]
3 years ago
15

Sylvanite is a mineral that contains 28.0% gold by mass. Determine how much sylvanite would you need to dig up to obtain 81.0 g

of gold.
Mathematics
1 answer:
lidiya [134]3 years ago
3 0
Since Sylvanite only contains 28% gold by mass, then to obtain 81.0 grams of gold, x amounts of sylvanite must be mined. To determine x, we divide 81 grams by 28%. This equation is shown below:

0.28X = 81

X = 81/0.28
X = 289.29 grams

Therefore, 289.29 grams of sylvanite must be dug up to obtain 81 grams of gold.
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