14*3(36/2(1*3)/6
1 answer:
<h2>10.5</h2><h3>remember pemdas</h3>
- parentheses
- exponents <em>excluded for this problem</em>
- multiplication
- division
- addition
- subtraction
- parentheses
1 × 3 = 3
<h3>step 3. find 36 divided by 2</h3>36 ÷ 2 = 18
<h3>step 4. add the values together</h3>18 + 3 = 21
<h3>step 5. find 14 times 3</h3>14 × 3 = 42 <em>you can also do 7 × 6 and will get the same result because 7 is half of 14 and 3 is half of 6</em>
<h3>step 6. add what is outside the parentheses</h3>21 + 42 = 63
<h3>step 7. divide by 6</h3>63 ÷ 6 = 10.5 10 remainder of 3 <em>remainder means left over</em>
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Answer: B) Zinc will act as Anode
Explanation:
Standard reduction potential of zinc and nickel are:
Here Zinc undergoes oxidation by loss of electrons, thus act as anode as it has more negative reduction potential.
Nickel undergoes reduction by gain of electrons and thus act as cathode. as it has less negative reduction potential.
Where both are standard reduction potentials.
As the emf is positive, the reaction is spontaneous and reaction will occur.
Thus Zinc will act as anode.