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Fudgin [204]
2 years ago
15

When the bones have atrophy remodeling, what happens to their strength?

Physics
1 answer:
bazaltina [42]2 years ago
6 0

Answer:

Because you are gay

Explanation:

The day you born

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PLSSSSS HELP!!!!!!! ASAP!!!!! MARK BRAINLIEST!!!!
Ymorist [56]

Answer: I would say the answer is B.

Explanation: It looks and sounds the most correct.

5 0
2 years ago
Can someone check my answer thanks ! 2.The ability to do work or cause change is called A.velocity. B.energy.(I PICK B.) C.trans
Lelechka [254]
2 is B.  3 is D.   4 is C.   I think 5 is A.   6 is A.   7 is D.   I think you are all correct. Good Luck!
7 0
2 years ago
Read 2 more answers
A process with a negative change in enthalpy and a negative change in entropy will generally be:________
valentina_108 [34]

A process with a negative change in enthalpy and a negative change in entropy will generally be: <u>spontaneous</u>.

<h3>Gibbs free energy:</h3>

Since the Gibbs free energy is a parameter that tells us whether a chemical reaction is spontaneous (Gibbs free energy less than 0) or nonspontaneous (Gibbs free energy greater than 0) in this situation, we can describe it mathematically as:

                                      ΔG = ΔH - TΔS

Therefore, any process with a negative change in enthalpy and a positive change in entropy will be spontaneous. If the enthalpy and the entropy are both negative, the subtraction becomes always negative, for which the Gibbs free energy is also negative.

One of the most crucial thermodynamic functions for the characterization of a system is the Gibbs free energy. It influences results like the voltage of an electrochemical cell and the equilibrium constant for a reversible reaction, among others.

Learn more about spontaneous here:

brainly.com/question/16975806

#SPJ4

3 0
1 year ago
Through what potential difference would you need to accelerate an alpha particle, starting from rest, so that it will just reach
Svetlanka [38]

Answer:

\Delta V    = 1.8 \times 10^7 V

Explanation:

GIVEN

diameter = 15 fm  =15 \times 10^{-15}m

we use here energy conservation

K_{i}+U_{i} =K_{f}+U_{f}

there will be some initial kinetic  energy but after collision kinetic energy will zero

K_{i} + 0 = 0 + \frac{1}{4 \pi \epsilon _{0}} \frac{(2e)(92e)}{7.5 \times 10^{-15}}

on solving these equations we get kinetic energy initial

KE_{i} = 5.65\times 10 ^{-12} \times \frac  {1 eV}{1.6 \times 10^{-19}}

KE_{i} = 35.33 J ..............(i)

That is, the alpha particle must be fired with 35.33 MeV of kinetic energy. An alpha particle with charge q = 2  e

and gains kinetic energy K  =e∆V  ..........(ii)

 by accelerating through a potential difference ∆V

Thus the alpha particle will

just reach the {238}_U nucleus after being accelerated through a potential difference  ∆V

equating (i) and second equation we get

e∆V  = 35.33 Me V

\Delta V = \frac{35.33}{2}  MV\\\Delta V    = 1.8 \times 10^7 V

7 0
3 years ago
A force of 600 N is acting on a motorcycle that has a mass of 240 kg. What is the acceleration of the motorcycle?
Verdich [7]

Answer:

2.5m/s2

Explanation:

The following were obtained from the question:

F = 600N

M = 240 kg

a =?

Recall: F = Ma

a = F/M

a = 600/240

a = 2.5m/s2

Therefore, the acceleration of the motorcycle is 2.5m/s2

7 0
3 years ago
Read 2 more answers
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