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Fudgin [204]
3 years ago
15

When the bones have atrophy remodeling, what happens to their strength?

Physics
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

Because you are gay

Explanation:

The day you born

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A positive rod is placed to the left of sphere A ,and the spheres are separated
Romashka [77]
When a positive rod is placed to the right of sphere B, and the spheres are separated, the reason behind this is the same charge on the sphere as the rod i.e. the right of the sphere also had a positive charge. Thus, the same positive charges could not reside on the right side surface of the sphere due to which it separation happens.

Read more on Brainly.com - brainly.com/question/4135790#readmore
5 0
3 years ago
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What rule does static electricity follow
Luba_88 [7]
Static electricity works when there is an imbalance of positive and negative charges, and thus causes a little spark.
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3 years ago
BEST ANSWER GETS BRAINLIEST!
wel

Answer:

Distance = 16.9 m

Explanation:

We are given;

Power; P = 70 W

Intensity; I = 0.0195 W/m²

Now, for a spherical sound wave, the intensity in the radial direction is expressed as a function of distance r from the center of the sphere and is given by the expression;

I = Power/Unit area = P/(4πr²)

where;

P is the sound power

r is the distance.

Thus;

Making r the subject, we have;

r² = P/4πI

r = √(P/4πI)

r = √(70/(4π*0.0195))

r = √285.6627

r = 16.9 m

8 0
3 years ago
Explain why rolling friction is lesser than sliding friction <br> Pls ans this
larisa [96]

Answer:

As the area of contact is less in the case of rolling than in the case of sliding, rolling friction is less than the sliding friction.

8 0
3 years ago
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An engine extracts 452.8kJ of heat from the burning of fuel each cycle, but rejects 266.7 kJ of heat (exhaust, friction,etc) dur
Svetlanka [38]

Answer: The thermal efficiency of the engine is 41.09 %.

Explanation:

Efficiency is the ratio of the useful work performed to the total energy expended or heat taken in.

Formula for thermal efficiency of engine is

\eta=1- \frac{Q_2}{Q_1}\times 100

\eta = efficiency

{Q_2} = heat rejected = 266.7 kJ

{Q_1} = heat extracted = 452.8 kJ

Putting in the values we get:

\eta=1- \frac{266.7 kJ}{452.8 kJ }\times 100

\eta=0.41\times 100

\eta =41.09\%

The thermal efficiency of the engine is 41.09 %.

7 0
4 years ago
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