U did it the way i asked. nice lol. its plasma btw
Answer:
a) the maximum transverse speed of a point on the string at an antinode is 5.9899 m/s
b) the maximum transverse speed of a point on the string at x = 0.075 m is 4.2338 m/s
Explanation:
Given the data in the question;
as the equation of standing wave on a string is fixed at both ends
y = 2AsinKx cosωt
but k = 2π/λ and ω = 2πf
λ = 4 × 0.150 = 0.6 m
and f = v/λ = 260 / 0.6 = 433.33 Hz
ω = 2πf = 2π × 433.33 = 2722.69
given that A = 2.20 mm = 2.2×10⁻³
so
= A × ω
= 2.2×10⁻³ × 2722.69 m/s
= 5.9899 m/s
therefore, the maximum transverse speed of a point on the string at an antinode is 5.9899 m/s
b)
A' = 2AsinKx
= 2.20sin( 2π/0.6 ( 0.075) rad )
= 2.20 sin( 0.7853 rad ) mm
= 2.20 × 0.706825 mm
A' = 1.555 mm = 1.555×10⁻³
so
= A' × ω
= 1.555×10⁻³ × 2722.69
= 4.2338 m/s
Therefore, the maximum transverse speed of a point on the string at x = 0.075 m is 4.2338 m/s
Answer:
If efficiency is .22 then W = .22 * Q where Q is the heat input
Heat Input Q = 2510 / .22 = 11,400 J
Heat rejected = 11.400 - 2510 = 8900 J of heat wasted
Also, 8900 J / (4.19 J / cal) = 2120 cal
The average current is 0.10 A.
<h3>Current </h3>
Charge moving through a location on a circuit at a constant rate is called current. When numerous coulombs of charge pass over a wire's cross section in a circuit, it produces a large current. It is not necessary for a wire to be moving at a fast speed in order to have a high current if the charge carriers are tightly packed into the wire. To put it another way, many charge carriers traveling through the cross section is sufficient; they do not need to travel a great distance in a single instant. The amount of charges that flow through a cross section of wire on a circuit, as opposed to how far they travel in a second, is what determines current.
A charge of 12 c passes through an electroplating apparatus in 2. 0 min. what is the average current?
Learn more about current here:
brainly.com/question/2264542
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Answer:
zero
Explanation:
For the box remaining at rest, the total acceleration on the box must be zero. Since force F = m*a, the force F must also be zero.