The minimum value for g(x)=x² - 10x + 16 is -9
<h3>How to determine the minimum value?</h3>
The function is given as:
g(x)=x² - 10x + 16
Differentiate the function
g'(x) = 2x - 10
Set the function 0
2x - 10 = 0
Add 10 to both sides
2x = 10
Divide by 2
x = 5
Substitute 5 for x in g(x)
g(5)=5² - 10*5 + 16
Evaluate
g(5) = -9
Hence, the minimum value for g(x)=x² - 10x + 16 is -9
Read more about quadratic functions at:
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DE is parallel to BC since D is the midpoint of
AB and E is the midpoint of AC.
<span>
Thus, DE and BC have the same slope (0.5) and basing on the formula for
midpoint, the length of DE would be the equal half of BC and is equal to 1.6
units</span>
The slope and length of DE, if the slope and
length of BC are 0.5 and 3.2 units, respectively are 0.5 and 1.6
respectively.
I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
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The correct Option is (C) 5x(3x^2 + 4)
Explanation:
15x^3 + 20x
Take common terms out:
5x(3x^2 + 4) Which is option C.
Answer: C. 3.2 × 10^4
Step-by-step explanation:
for this case the multiplication of the values with exponent are summed, as the exponent are the 6 and -3
6 - 3 = 3
this will be the exponent of the common value which is the 10.
after you only need to multiply 8 and 4 by separate the
8 * 4 = 32.
then we only need to place the values one by one
32 × 10^3
3 is the result of the sum of the exponent.
10 is the common value.
32 is the result of the product.
if we add another zero to the multiplication we get 3.2 and exponent finish with one more zero, then we get this result
3.2 × 10^4
because of that the C is the correct answer, keep in mind that the other answers do not apply correctly the rule of the exponent, because the rest of answer give us wrong answer with final result of the exponent.
