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1 year ago

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How do you find the mean absolute deviation MAD

1 answer:

lawyer [7]1 year ago

5 0

Answer:

Most of the time you can go on a website that can cauculate it.

Step-by-step explanation:

How to cauculate the MAD:

Take each number in the data set, subtract the mean, and take the absolute value. Then take the sum of the absolute values. Now compute the mean absolute deviation by dividing the sum above by the total number of values in the data set. Finally, round to the nearest tenth.

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Jayden used a Groupon at the local pizza shop. Instead of paying $15, for the pizza, he paid $12.

DENIUS [597]

Answer:

She is correct because they need to find how much is the discounted price, which is 3. So to see what percentage it is, they need to see how much 3 is worth in comparison to 15. If we spilt 15 into 5 parts to make every part worth 20%, the answer would be 3. Thus Arianna is correct.

Step-by-step explanation:

7 0

2 years ago

Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i

Vsevolod [243]

$\huge \boxed{\mathfrak{Answer} \downarrow}$

$\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\$

Multiply both numerator and denominator of $\sf \frac{5-3i}{-2-9i} \\$ by the complex conjugate of the denominator, -2+9i.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)}) \\$

Multiplication can be transformed into difference of squares using the rule: $\sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$ .

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}}) \\$

By definition, i² is -1. Calculate the denominator.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85}) \\$

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

$\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85}) \\$

Do the multiplications in $\sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right)$ .

$\large \bf \: Re(\frac{-10+45i+6i+27}{85}) \\$

Combine the real and imaginary parts in -10+45i+6i+27.

$\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85}) \\$

Do the additions in $\sf-10+27+\left(45+6\right)i$ .

$\large \bf Re(\frac{17+51i}{85}) \\$

Divide 17+51i by 85 to get $\sf\frac{1}{5}+\frac{3}{5}i \\$ .

$\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i) \\$

The real part of $\sf \frac{1}{5}+\frac{3}{5}i \\$ is $\sf \frac{1}{5} \\$ .

$\large \boxed{\bf\frac{1}{5} = 0.2} \\$

3 0

2 years ago

Evaluate. 7^3 <br> A) 21<br> B) 49<br> C) 81<br> D) 343

Mademuasel [1]

The answer is a 73/3=21

5 0

2 years ago

Read 2 more answers

Order the integers {0, |-20|, -3, 19, -13} from least to greatest

tatiyna

Answer:

-20, -13, -3 0, 19

Step-by-step explanation:

With negative the higher the number the lower the value

4 0

2 years ago

Simplify and find the value of the expression if x=2 and y = 13xy (4x- 5y) +3xsquare y

maria [59]

Answer:

13 + 4(2) - 5(13) + 3

<em>multiply the numbers</em>

13 + 8 - 65 + 3

<em>calculate the sum or difference </em>

= -41

Step-by-step explanation:

3 0

2 years ago