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Naily [24]
3 years ago
15

Write balanced net ionic equations that show the two relevant ionization steps for glycine

Chemistry
1 answer:
Maslowich3 years ago
4 0
Write chemical equations and corresponding equilibrium expressions for each of the two ionization steps of carbonic acid.
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Rank and explain how the freezing point of 0.100 m solutions of the following ionic electrolytes compare. List from lowest freez
Elden [556K]

Answer:

The solutions are listed from the lowest freezing point to highest freezing point.

Mg₃(PO₄)₂ -  AlBr₃ - BeBr₂ -  KBr

Explanation:

Colligative property of freezing point, is the freezing point depression.

Formula is:

ΔT = Kf . m . i

Where ΔT = T° freezing pure solvent - T° freezing solution

Kf is the cryoscopic constant

m is molality and i is the Van't Hoff factor (number of ions, dissolved in solution)

In this case, T° freezing pure solvent is 0° because it's water, so the Kf is 1.86 °C/m, and m is 0.1 molal.

The i modifies the T° freezing solution. The four salts, are ionic compounds, so for each case:

BeBr₂  → Be²⁺  +  2Br⁻   i = 3

AlBr₃ →  Al³⁺  + 3Br⁻   i = 4

Mg₃(PO₄)₂  →  3Mg²⁺  +  2PO₄⁻³    i = 5

KBr →  K⁺  +  Br⁻   i = 2

Solution of Mg₃(PO₄)₂ will have the lowest temperature of freezing and the solution of KBr, the highest (always lower, than 0°).

8 0
3 years ago
7. A cyclist starting from rest accelerates at a rate of 6 m/s until she reaches 30 m/s. How long
Hunter-Best [27]

Answer:

Explanation:

The given values are:

a= 6m/s²

u= 0 m/s

v = 30 m/s

t= ?

The formula is :

a=\frac{v-u}{t}

thus,

t=\frac{v-u}{a}\\t=\frac{30-0}{6}\\t= 5 seconds

4 0
3 years ago
The temperature of a 15-g sample of lead metal increases from 22 °C to 37 °C upon the addition of 29.0 J of heat. The specific h
Kryger [21]

Answer:

0.13 J/g.°C.

Explanation:

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by lead (Q = 29.0 J).

m is the mass of lead (m = 15.0 g).

c is the specific heat capacity of lead (c = ??? J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT =  37 °C - 22 °C = 15.0 °C).

∵ Q = m.c.ΔT

<em>∴ c = Q/m.ΔT </em>= (29.0 J)/(15.0 g)(15.0 °C) = <em>01288 J/g.°C ≅ 0.13 J/g.°C.</em>

3 0
4 years ago
What are two examples of decomposers
bazaltina [42]

bacteria, and fungi are some examples

3 0
4 years ago
The main purpose of _____ is to distribute blood throughout the body
erastovalidia [21]

Answer:

Cardiovascular system

also known as the The circulatory system,

Explanation:

please mark branliest if this helped and rate

4 0
3 years ago
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