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vovangra [49]
3 years ago
12

How much heat energy is needed to heat 250 g of water from 200C to its boiling point and then completely vaporize it?

Chemistry
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer: 40.66kJ/mol.

Explanation:Assuming that pressure is equal to Explanation:Assuming that pressure is equal to 1 atm Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘C

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘C .

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘C .The amount of heat needed to allow one mole of water to undergo this phase change is called the enthalpy change of vaporization,

nge of vaporization, Δ

nge of vaporization, ΔH

nge of vaporization, ΔHvap

nge of vaporization, ΔHvap .

nge of vaporization, ΔHvap .For water at

nge of vaporization, ΔHvap .For water at 100

nge of vaporization, ΔHvap .For water at 100∘

nge of vaporization, ΔHvap .For water at 100∘C

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal to

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔ

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔH

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔHvap

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔHvap=

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔHvap=40.66 kJ/mol

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Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
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Answer:

The concentration of COF₂ at equilibrium is 0.296 M.

Explanation:

To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:

   2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I      2.00              0              0

C      -2x              +x            +x

E   2.00 - 2x         x              x

Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".

Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852

The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M

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3 years ago
An animal which eats plants and animals is a(n)
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Answer:

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Explanation: An <u>omnivore</u> is a kind of animal that eats either other animals or plants. Some omnivores will hunt and eat their food, like carnivores, eating herbivores and other omnivores. Some others are scavengers and will eat dead matter. Many will eat eggs from other animals.

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A 2.5 mol sample of phosphorus pentachloride, PCl5 dissociates at 160C and 1.00atm to give 0.338 mol of phosphorus trichloride a
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Explanation:

Moles of phosphorus pentachloride present initially = 2.5 mol

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PCl_5\rightleftharpoons PCl_3+Cl_2

Initially

2.5 mol      0    0

At equilibrium:

(2.5 - x) mol      x     x

So, from above, the moles of phosphorus trichloride at equilibrium , x= 0.338 mol

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