Question

Calculate the molarity of 6.631 g NANO3 in 100.0 mL of solutionadd stepss

Answer 1

Answer:

Explanation:

Mole weight of NaNO3 ====> ~~ 85 gm

6.631 / 85   = # moles in .1 liter

6.631/85  / (.1)  = .78 M

Answer 2

Answer:

0.7802 M

Explanation:

Data:

• V (volume) = 100.0 mL → V = 0.1000 L
• m (mass) = 6.631 g → n = 0.07802 mol

Wanted:

• M (Molarity)

Equation:

M = $\frac{mol}{L}$

Solution:

1. Convert mL to L:

• V = 100.0 mL x $\frac{1 L}{1000 mL}$ = 0.1000 L

2. Convert g to mol:

• n = $\frac{6.631 g}{84.9947 g/mol}$ = 0.07802 mol

3. Molarity Equation:

• M = $\frac{0.07802 mol}{0.1000 L}$ = 0.7802 M