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prisoha [69]
2 years ago
11

Calculate the molarity of 6.631 g NANO3 in 100.0 mL of solutionadd stepss

Chemistry
2 answers:
sp2606 [1]2 years ago
6 0

Answer:

Explanation:

Mole weight of NaNO3 ====> ~~ 85 gm

6.631 / 85   = # moles in .1 liter

6.631/85  / (.1)  = .78 M

riadik2000 [5.3K]2 years ago
3 0

Answer:

0.7802 M

Explanation:

<u>Data:</u>

  • V (volume) = 100.0 mL → V = 0.1000 L
  • m (mass) = 6.631 g → n = 0.07802 mol

<u>Wanted: </u>

  • M (Molarity)

<u>Equation: </u>

M = \frac{mol}{L}

<u>Solution:</u>

1. Convert mL to L:

  • V = 100.0 mL x \frac{1 L}{1000 mL} = 0.1000 L

2. Convert g to mol:

  • n = \frac{6.631 g}{84.9947 g/mol} = 0.07802 mol

3. Molarity Equation:

  • M = \frac{0.07802 mol}{0.1000 L} = 0.7802 M
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