What is the pH of a solution with an [H+] = 4.73x10^-7 M

Chemistry

1 answer:

Mice21 [21]4 years ago

6 0

Answer:

The answer to your question is pH = 6.3

Explanation:

Data

pH = ?

[H⁺] = 4.73 x 10⁻⁷ M

pH is the measure of the concentration of [H⁺]. pH measures the acidity of the solution. If the value of pH is between 0 and 6.9, the solution is an acid. If the pH is 7.0 the solution is neutral and if the pH is between 7.1 and 14, the solution is an alkali.

Formula

pH = -log[H⁺]

Substitution

pH = -log[4.73 x 10⁻⁷]

-Simplification

pH = - (-6.3)

-Result

pH = 6.3

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6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/

Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

$A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}$

(b) Percent transmission

$A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}$

7) Absorbance

$A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}$