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Julli [10]
3 years ago
15

Arrange the elements in order of increasing ionization energy. Use the

Chemistry
2 answers:
Vanyuwa [196]3 years ago
7 0

Answer:

Gallium, Phosphorous, Chlorine, Flurione

Explanation:

for plato users :)

UNO [17]3 years ago
5 0

Answer:

Gallium, Phosphorus, Chlorine, Fluorine

Explanation:

Arrange the elements in order of increasing ionization energy. Use the periodic table to identify their positions on the table.

Drag each tile to the correct box.

Tiles

chlorinefluorinegalliumphosphorus

Sequence

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I NEED HELP PLEASE, THANKS! :)
TEA [102]

Answer:

K=\frac{[CaO][CH_{4}][H_{2}O ]^{2}  }{[CaCO_{2}][H_{2}]^4  }

Explanation:

The equilibrium expression is the K value equal to the product of the concentrations of the products over the product of the concentrations of the reactants.  If there is a coefficient in front of the compound, raise the molecule to that power.

Since K is big, more product is expected.  This is because of mathematic principles.  A large numerator with a small denominator will produce a large number.

3 0
2 years ago
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On combustion of 0.2 gm of organic compound gave 0.147g of CO2, 0.12g of H2O and 74.6 ml of nitrogen gas at STP. Find emperical
zhuklara [117]

Answer:

0.2 is conpound Co2 STP.

Explanation:

on combustion of 0.2 gm of organic compound gave 0.147g of CO2, 0.12g of H2O and 74.6 ml of nitrogen gas at STP. Find emperical formula of compound.?

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5 0
2 years ago
A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known mass of KHP was titra
Eddi Din [679]

Answer:

See explanation below

Explanation:

In order to calculate this, we need to use the following expression to get the concentration of the base:

MaVa = MbVb (1)

We already know the volume of NaOH used which is 13.4473 mL. We do not have the concentration of KHP, but we can use the moles. We have the mass of KHP which is 0.5053 g and the molecular formula. Let's calculate the molecular mass of KHP:

Atomic weights of the elements to be used:

K = 39.0983 g/mol;  H = 1.0078 g/mol;  C = 12.0107 g/mol;  O = 15.999 g/mol

MM KHP = (1.0078*5) + (39.0983) + (8*12.0107) + (4*15.999) = 204.2189 g/mol

Now, let's calculate the mole of KHP:

moles = 0.5053 / 204.2189 = 0.00247 moles

With the moles, we also know that:

n = M*V (2)

Replacing in (1):

n = MbVb

Now, solving for Mb:

Mb = n/Vb  (3)

Finally, replacing the data:

Mb = 0.00247 / (13.4473/1000)

Mb = 0.184 M

This would be the concentration of NaOH

8 0
3 years ago
What do you think of my lab report so far?
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Fix ur transition, it sounds choppy

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3 years ago
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A 13.00 g sample of citric acid reacts with an excess of baking soda as shown in the equation.
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