Yes is is, is your area still there?
Answer:
Step-by-step explanation:
We need to evaluate if thickness of a 10 gauge metal sheet is a requiered in the process that means 3.416 mm thick. So that should be our null hypothesis; μ₀ = 3.416 and based on sample data, we will formulate an alternative hypothesis taking into account the mean, and standard deviation obtained. We surely will have better information to take a decision
The radius the wheel (circle) is 15 ft a circle is equal to 360° so
1the central angle is: 5/360=24°
the circumference is: 2 π 24= 150.7ft
The arc is: 150.7/24= 6.28ft
The area of sector is: = 1/20 * Area of circle
<span>= 1/20 * pi * (25)^2 </span>
<span>= 98.17 feet^2
</span>I hope that this is helpful :)
Answer:
a. 
Step-by-step explanation:
Since f(x) is the function for the populational density at a certain sidewalk for a 5 mile stretch, a definite integral of that function will yield the total number of people within the integration intervals. If we are interested in the number of people in the whole 5 mile stretch, we must integrate f(x) from x = 0 miles to x = 5 miles:
Therefore, the answer is alternative a.
Answer:
<h3>
ln (e^2 + 1) - (e+ 1)</h3>
Step-by-step explanation:
Given f(x) = ln and g(x) = e^x + 1 to get f(g(2))-g(f(e)), we need to first find the composite function f(g(x)) and g(f(x)).
For f(g(x));
f(g(x)) = f(e^x + 1)
substitute x for e^x + 1 in f(x)
f(g(x)) = ln (e^x + 1)
f(g(2)) = ln (e^2 + 1)
For g(f(x));
g(f(x)) = g(ln x)
substitute x for ln x in g(x)
g(f(x)) = e^lnx + 1
g(f(x)) = x+1
g(f(e)) = e+1
f(g(2))-g(f(e)) = ln (e^2 + 1) - (e+ 1)
