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iVinArrow [24]
2 years ago
15

A car travels at 30 1/5 miles in 2/3 of an hour. What is the average speed, in miles per hour

Mathematics
2 answers:
marin [14]2 years ago
7 0

ANSWER:

45 3/10 mph

decimal form: 45.3 mph

Step-by-step explanation:

30 1/5 /2 = 15 1/10

15 1/10 x 3 = 45 3/10 mph

So hence, your answer is 45 3/10 mph. In decimal format, it can be 45.3

jasenka [17]2 years ago
4 0

Answer:

45.3 miles/h

Step-by-step explanation:

The answer is 45.3 miles/h

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40,583 in word format .......................................................... ......... .........
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Forty-thousand, five-hundred eighty-three.
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3 years ago
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Xelga [282]

Answer:

-27

Step-by-step explanation:

order of operations 2÷2 = 1 +53 =54

3x1 = 3 -5 = -2

54÷-2 = -27

5 0
2 years ago
Evaluate the cosine if the angle of rotation which contains the point (9, -3) on its terminal side
Liono4ka [1.6K]

so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant

\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{9}}{\stackrel{hypotenuse}{\sqrt{90}}}\implies \stackrel{\textit{rationalizing the denominator}}{\cfrac{9}{\sqrt{90}}\cdot \cfrac{\sqrt{90}}{\sqrt{90}}\implies \cfrac{9\sqrt{90}}{90}}\implies \cfrac{\sqrt{90}}{10}\implies \cfrac{3\sqrt{10}}{10}

6 0
3 years ago
A random sample is drawn from a population with mean μ = 66 and standard deviation σ = 5.5. use table 1.
creativ13 [48]
<span>A random sample is drawn from a population with mean μ = 66 and standard deviation σ = 5.5. use table 1.
a. is the sampling distribution of the sample mean with n = 16 and n = 36 normally distributed? yes, both the sample means will have a normal distribution. no, both the sample means will not have a normal distribution. no, only the sample mean with n = 16 will have a normal distribution. no, only the sample mean with n = 36 will have a normal distribution.
b. can you use the standard normal distribution to calculate the probability that the sample mean falls between 66 and 68 for both sample sizes? yes, for both the sample sizes, standard normal distribution could be used. no, for both the sample sizes, standard normal distribution could not be used. no, only for the sample size with n = 16, standard normal distribution could be used. no, only for the sample size with n = 36, standard normal distribution could be used.
c. calculate the probability that the sample mean falls between 66 and 68 for n = 36. (round intermediate calculations to 4 decimal places, "z" value to 2 decimal places, and final answer to 4 decimal places.)</span>
7 0
3 years ago
Please help with #49
Anuta_ua [19.1K]

Answer:

A

Step-by-step explanation:

The inverses of functions are basically the Xs and Ys swapped. For example, the inverse of (2,-3) is (-3,2).

Thus, the inverse of (-2,4), (3,2), and (-6,10) will be (4,-2), (2,3), and (10,-6).

the answer is A.

8 0
3 years ago
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