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Murrr4er [49]
2 years ago
15

Step by step please -- algerbra 2 w(n) = 4n +2 ; find w(3n)

Mathematics
1 answer:
viva [34]2 years ago
4 0

Answer:

12n+2

Step-by-step explanation:

w(n)=4n+2

w(3n)=4(3n)+2

w(3n)=12n+2

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saul85 [17]

\large\underline{\sf{Solution-}}

<u>Let us assume that:</u>

\sf \longmapsto x =  \sqrt{6 +  \sqrt{6 +  \sqrt{6 + ... \infty } } }

We can also write it as:

\sf \longmapsto x =  \sqrt{6 +  x }

Squaring both sides, we get:

\sf \longmapsto  {x}^{2}  =6 +  x

\sf \longmapsto  {x}^{2} - x - 6  =0

By splitting the middle term:

\sf \longmapsto  {x}^{2} - 3x + 2x - 6  =0

\sf \longmapsto x(x - 3) + 2(x - 3 ) =0

\sf \longmapsto (x+ 2)(x - 3 ) =0

<u>Therefore:</u>

\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}

\sf \longmapsto x =  - 2,3

<u>But x cannot be negative. </u>

\sf \longmapsto x = 3

Therefore, the value of the expression is 3.

\large\underline{\sf{Verification-}}

Given:

\sf\longmapsto x=3

We can also write it as:

\sf\longmapsto x = \sqrt{9}

\sf\longmapsto x = \sqrt{6+3}

\sf\longmapsto x = \sqrt{6 + \sqrt{9}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}

This pattern will continue.

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}

7 0
3 years ago
Factor the polynomial: x(5x-8)-2(5x-8)
sertanlavr [38]
<span>x(5x-8)-2(5x-8) =(5x-8)(x-2)
Answer is </span><span>C. (5x-8)(x-2)</span>
3 0
3 years ago
Which statement is true for the graph of f(x) = 2x2 - 6x2 - 48x + 24?<br> (Answers attached)
Fudgin [204]

Answer:

min = (4, -136) ; max = (-2,80)

Step-by-step explanation:

The option is B

3 0
2 years ago
Solve this equation 3x + 5 = 7x – 7
Mama L [17]
Add 7 to both sides
3x + 12 = 7x
Subtract 3x
12 = 4x
Divide by 4
x = 3
4 0
3 years ago
Read 2 more answers
Need this please!!! Graph Y=-5x-2!!! Thanks. :-)
Andreyy89

Graph the line using the slope and y-intercept, or two points.

Slope= -5

y- intercept= (0,2)

The answer has two points (0,2) and (1,-3) place them and then make a line going left through them.

7 0
2 years ago
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